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3 years ago

How many minutes are there from 3.24pm to 4.10pm

Mathematics

2 answers:

pochemuha3 years ago

8 0

86 minutes would have passed.

monitta3 years ago

3 0

86 minutes I agree with your answer

You might be interested in

140÷(x+9)+(x+4)² when x =1 show work

Dmitrij [34]

Answer:

Step-by-step explanation:

If x=1, then it's equal to 140/(1+9, or 10)+(1+4, or 5)^2, and that is equal to 140/10+5^2, or 140/10+25, and 140/10=14, and 14+25=39

brainliest pls

4 0

3 years ago

During a sale, every item in a store is 80% of its regular price

garri49 [273]

$10 multiply by .80 is $8
$10-$8 is $2 is sale price do this for all items.
$1 is .20 cents
$4 is .80 cents
$55 is $11
$120 is $24

6 0

3 years ago

Read 2 more answers

Find the area of an equilateral triangle (regular 3-gon) with the given measurement: 6-inch radius. A = sq. in.

levacccp [35]

The correct answer is 27√3

4 0

4 years ago

Read 2 more answers

Verify 3/4 + (7/2 + -3/8) = 3/4 + 7/2 + (-3/8)

Mrac [35]

Answer:

true

Step-by-step explanation:

Since the parenthesis do not have a negative on the outside, we don't need to distribute the negative sign. The equation is equal to each other

Hope that helps :)

6 0

3 years ago

Explain why sin^-1(sin(3pi/4))does not equal 3pi/4 when y=sin x and y=sin^-1 x are inverses.

Fofino [41]

Because they're not inverses, not exactly. $\sin x$ is not invertible on its entire domain because it's not one-to-one. There are infinitely many values of $x$ such that $\sin x=0$ , for example.

The standard function $\sin^{-1}x$ has a domain of $-1\le x\le1$ and outputs values between $-\dfrac\pi2$ and $\dfrac\pi2$ . This means that its inverse, $\sin x$ , is indeed its inverse as long as $-\dfrac\pi2\le x\le\dfrac\pi2$ .

$\dfrac{3\pi}4$ is larger than $\dfrac\pi2$ and thus does not fall in the "invertible part" of the domain of $\sin x$ . We have

$\sin\dfrac{3\pi}4=\dfrac1{\sqrt2}$

which is a value between -1 and 1, so that

$\sin^{-1}\left(\sin\dfrac{3\pi}4\right)=\sin^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4$

If we wanted to recover $\dfrac{3\pi}4$ , we'd have to redefine $\sin^{-1}x$ or define a new inverse function that works on a different branch of the domain of $\sin x$ .

7 0

3 years ago