<u>Answer:</u>
<em>Customer administrations</em><em> supervisors interface an organization's imaginative endeavours with publicists' needs, from driving the main gathering on another record to looking into </em><em>news sources for a crusade</em><em>. </em>
<u>Explanation:</u>
They keep up associations with administrators of customer organizations, supervise the office's record group over all orders and create procedures for customers.
So, the customer administrations supervisor is responsible for all parts of the conveyance of work to the customer. Be that as it may, the record head's job goes past only giving a customer what he needs.
Answer: higher than
Explanation: The stockholders of companies in the infant industry gain when they are protected from world competition
-Consumes in that country will therefore pay a price higher than the world price.
Answer: The actual rate of the mortgage is 5.27%.
Since we're taking two mortgages for a total of $200,000 for 30 years, we can find the actual rate of the mortgage by finding the weighted average of the two rates. The weights in this case will be the proportion of loan taken at each rate
We have
Rates Weights Rates * Weights
4.15 0.80 
9.75 0.20
Total 5.27%
Answer:
Incomplete question
First aspect of the question is typed below.
The shape of the distribution of the time required to get an oil change at a 20-minute oil-change facility
is unknown. However, records indicate that the mean time is 2l.2-minutes, and the standard deviation 3.5 minutes.
Explanation:
Employees bonus $50
35 oil changes between 10:00 am to 12:00pm
n = 35
10% changes
So, the z - score can be calculated using
z-score = InvNorm(0.10)
z-score = -1.28
So, given that,
Standard deviation is 3.5minutes
σ = 3.5 minutes
Mean time is 21.2 minutes
μx = 21.2 minutes
Then,
σx = σ / √n
σx = 3.5 / √35
σx = 0.5916 minutes
Then, Z score can be written as
Z = (x - μx) / σx
-1.28 = (x - 21.2) / 0.5916
Cross multiply
-1.28 × 0.5916 = x - 21.2
-0.7573 = x - 21.2
x = 21.2 - 0.7573
x = 20.443 minutes
There is a 10% chance of being at or below a mean oil-change time of 20.44 minutes