Answer:
The sum of the first 880 terms in the sequence is 2,273,920.
Step-by-step explanation:
Arithmetic sequence:
The difference between consecutive terms is always the same, called common difference, and the nth term is given by:

In which d is the common difference.
Sum of the first n terms:
The sum of the first n terms of an arithmetic sequence is given by:

ai = ai-1 + 6
This means that 
In this question:
Sum of the first 800 terms, so 
First term is -53, so 
The 880th term is:

Sum

The sum of the first 880 terms in the sequence is 2,273,920.
Answer:
-2
Step-by-step explanation:
(5 - a) = 20 + (6a -1) . . . . . 5-a is 20 greater than 6a-1
5 = 7a +19 . . . . . . . . . . . . . add a, collect terms
-14 = 7a . . . . . . . . . . . . . . . subtract 19
-2 = a . . . . . . . . . . . . . . . . divide by 7
The value of the variable is -2.
_____
<u>Check</u>
5 - (-2) = 7
6(-2) -1 = -13
7 is 20 greater than -13, so the answer checks OK.
3
3(2x3+3x-4)
Mark brainliest please
Answer:
Step-by-step explanation:
balls
Answer:
Graph C
<em>Because i starts at the point (0,5)</em>
Hope I Helped