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3 years ago

Aaron wants to divide the trail mix equally into 6 bags to give to his friends.How much trail mix will be in each bag?

Mathematics

2 answers:

emmainna [20.7K]3 years ago

8 0

1 is the answer because if you divided 6 by 6 you get 1

Nataly_w [17]3 years ago

6 0

Wouldn't you divide each ingredient by 6?

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Convert 3 pints per second to gallons per minute

exis [7]

24 hopes that is right

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3 years ago

What is 1/4 subtract 1 and 1/2 A. 1/2 B. 1/8 C. 3/4 D. 3/8

Lelu [443]

Answer:

-1 1/4

Step-by-step explanation:

1/4 - (1 1/2)

Get a common denominator

1/4 - 1 2/4

Take the larger number and subtract the smaller number and take the sign of the larger

1 2/4 - 1/4 = 1 1/4

The sign of the larger was negative

-1 1/4

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Csf%2023%289x%2B6%29%3D6x%2B4" id="TexFormula1" title="\sf 23(9x+6)=6x+4" alt="\sf 23(9x+6)=

ozzi

The value of x from the given expression is; x= -2/3

<h3>Solving one-variable equations</h3>

The given expression is;

23(9x+6) = 6x + 4.

Hence, when we expand the equation; we have;

207x + 138 = 6x +4

207x - 6x = 4 - 138

201x = -134

x = -134/201

x = -2/3

Read more on one-variable equations;

brainly.com/question/21528555

4 0

2 years ago

Read 2 more answers

Solve for m: <br> 8(m + 2) = 3(12 - 4m)

Tema [17]

Answer:

m=1

Step-by-step explanation:

step 1: 8(m + 2) = 3(12 - 4m) remove the parentheses

step 2: 8 m + 2 = 3 12 - 4m move the terms

step 3: 8m+ 12m= 36 - 16 collect like terms and calulate

step 4: 20m=20 divide both sides

solution: m=1

3 0

3 years ago

Read 2 more answers

The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there a

Anettt [7]

Answer:

1) The size of the colony after 4 days is 6553 mosquitoes

2) After $t = 4.9\ days$

Step-by-step explanation:

To answer this question you must use the growth formula

$N = N_0e ^ {kt}$

Where

$N_0$ is the initial population of mosquitoes = 1000

t is the time in days

k is the growth rate

N is the population according to the number of days

We know that when t = 1 and $N_0=1000$ then N = 1600

Then we use these values to find k.

$1600 = 1000e ^{k(1)}\\\\\frac{1600}{1000} = e ^ k\\\\ln(\frac{1600}{1000}) = k\\\\k = 0.47$

Now that we know k we can find the size of the colony after 4 days.

$N = 1000e ^ {0.47(4)}\\\\N = 6553\ mosquitoes$

To know how long it should take for the population to reach 10,000 mosquitoes we must do N = 10000 and solve for t.

$10000 = 1000e ^ {0.47t}\\\\10 = e ^ {0.47t}\\\\ln(10) = 0.47t\\\\t = \frac{ln(10)}{0.47}\\\\t = 4.9\ days$

6 0

3 years ago