All categories

4 years ago

Center (3, -2) Radius = 3

Mathematics

1 answer:

mel-nik [20]4 years ago

3 0

Answer:

x^2-6x+y^2+4y=-4

Step-by-step explanation:

I am assuming you want the equation of the circle. We know that the equation of a circle is (x-h)^2 + (y-k)^2 =r^2, where r is the radius, and h and k are the x and y coordinates of the center respectively. We can solve for this by plugging in the numbers.

(x-3)^2+(y+2)^2=3^2

x^2-6x+9+y^2+4y+4=9

x^2-6x+y^2+4y=-4

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Answer:

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Step-by-step explanation:

$3x^2-12x$ cannot be factorised in the form (x+b)(x-b) unless one of the b's is zero, so I wonder if the expression is incomplete?

To factorise $3x^2-12x$ , take out the common factor $3x$ :

$\implies3x(x-4)$

Therefore, x = 0 and x = 4

- - - - - - - - -

$3x^2-12x$ factorised in the form (x+b)(x-b) would be $(3x+0)(x-4)$

but it is not usual to have a zero in a factorised form.

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