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kramer
3 years ago
6

What is the apparent solution to the system of equations graphed above?

Mathematics
2 answers:
Oksana_A [137]3 years ago
7 0
I think the answer is (-2,2)
Fiesta28 [93]3 years ago
5 0

we know that

The solution of the system of linear equation graphed is the intersection both graphs

so

The point of intersection is (-2,2)

therefore

<u>the answer is</u>

The solution is the point (-2,2)

see the attached figure to better understand the problem

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Picky Polls asked 1600 third-year college students if they still had their original major. According to the colleges, 50% of all
Reptile [31]

Answer:

The probability that less than 800 students who said they still had their original major is 0.50 or 50%.

Step-by-step explanation:

Let the random variable <em>X</em> be described as the number of third-year college students if they still had their original major.

The probability of the random variable <em>X</em> is, P (X) = <em>p</em> = 0.50.

The sample selected consisted of <em>n</em> = 1600 third-year college students.

The random variable <em>X </em>thus follows Binomial distribution with parameters n = 1600 and p = 0.50.

X\sim Bin(1600, 0.50)

As the sample size is large, i.e.<em>n</em> > 30, and the probability of success is closer to 0.50,  Normal approximation can be used to approximate the binomial distribution.

The mean of <em>X</em> is:

\mu_{x}=np=1600\times0.50=800\\

The standard deviation of <em>X</em> is:

\sigma_{x}=\sqrt{np(1-p}=\sqrt{1600\times0.50(1-0.50)}=20

It is provided that Picky Polls got less than 800 students who said they still had their original major.

Then the probability of this event is:

P(X

**Use the <em>z</em>-table for the probability.

Thus, the probability that less than 800 students who said they still had their original major is 0.50.

7 0
3 years ago
Susan, Deon, and Felipe sent a total of 160 text messages during the weekend. Felipe sent 4 times as many messages as Susan. Deo
Romashka [77]

Answer:

Susan sent 25 messages

Felipe sent 100 messages

Deon sent 35 messages

Step-by-step explanation:

160 = x + 4x + x + 10

160 = 6x + 10

6x = 150

x = 25

7 0
3 years ago
What is the value of X
bixtya [17]
All 3 angles have to add up to be 180 so the answer would be 90

5 0
3 years ago
Suppose total benefits and total costs are given by b(y) = 100y − 8y2 and c(y) = 10y2. what is the maximum level of net benefits
olga nikolaevna [1]
Whenever you face the problem that deals with maxima or minima you should keep in mind that minima/maxima of a function is always a point where it's derivative is equal to zero.
To solve your problem we first need to find an equation of net benefits. Net benefits are expressed as a difference between total benefits and total cost. We can denote this function with B(y).

B(y)=b-c
B(y)=100y-18y²

Now that we have a net benefits function we need find it's derivate with respect to y.

\frac{dB(y)}{dy} =100-36y

Now we must find at which point this function is equal to zero.

0=100-36y
36y=100
y=2.8

Now that we know at which point our function reaches maxima we just plug that number back into our equation for net benefits and we get our answer.

B(2.8)=100(2.8)-18(2.8)²=138.88≈139.

One thing that always helps is to have your function graphed. It will give you a good insight into how your function behaves and allow you to identify minima/maxima points.


3 0
3 years ago
Segment BDSegment BD is a perpendicular bisector of segment ACsegment AC . AB=6xAB=6x and CB=x+15CB=x+15 . What is the length of
jolli1 [7]
Since BD is the perpendicular bisector of AC, then AB = BD, so:
6x = x+15
5x=15
x=3
CB = 3+15 = 18
3 0
3 years ago
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