The description below proves that the perpendicular drawn from the vertex angle to the base bisect the vertex angle and base.
<h3>How to prove an Isosceles Triangle?</h3>
Let ABC be an isosceles triangle such that AB = AC.
Let AD be the bisector of ∠A.
We want to prove that BD=DC
In △ABD & △ACD
AB = AC(Thus, △ABC is an isosceles triangle)
∠BAD =∠CAD(Because AD is the bisector of ∠A)
AD = AD(Common sides)
By SAS Congruency, we have;
△ABD ≅ △ACD
By corresponding parts of congruent triangles, we can say that; BD=DC
Thus, this proves that the perpendicular drawn from the vertex angle to the base bisect the vertex angle and base.
Read more about Isosceles Triangle at; brainly.com/question/1475130
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Answer:
30/54
Step-by-step explanation:
1st make and equation so 5/9=x/54
now cross-multiply.
5/9=x/54
(5)*(54)=x*(9)
270=9x
you can flip the equation.
9x=270 (next divide both sides by 9)
x=30
so 30/54=5/9
hope this helps :)
Answer:
12.56
Step-by-step explanation:
The equation for the area of a circle is πr² (pi x r²). The first step is squaring r, the radius, which is 2. 2²=4. 4 x 3.14= 12.56
Angle BAD is equal angle ABD
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s leslie correct answer
