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Paraphin [41]
2 years ago
11

Two parallel lines are crossed by a transversal. Vertical and parallel lines h and i are cut by transversal g. At the intersecti

on of lines h and g, the uppercase right angle is 70 degrees and the bottom left angle is x degrees.
Mathematics
1 answer:
eduard2 years ago
3 0

Answer:

x = 70

Step-by-step explanation:

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What is the perimeter of the quadrilateral?
olasank [31]

Answer:

24.6

Step-by-step explanation:

you multiply them all by two then add them together. :P

6 0
2 years ago
Read 2 more answers
Select all of the fractions that are equivalent to -2/3 –3/-2 -3/2 2/-2 2/-3 2/3 -2/-3 Please hurry and help I really need it​
lianna [129]

Answer:

2/-3

Step-by-step explanation:

Hope this helped. And I know that you can choose more than one, but I'm pretty sure this is the only one that's equivalent to -2/3

5 0
3 years ago
The map of a walking trail is drawn a coordinate grid with three points of interest. The trail starts at R(-3,2) and goes to S(2
Nezavi [6.7K]

Answer:

12 units

Step-by-step explanation:

Given that :

R(-3,2)

S(2,2)

T(2,-5).

The total length ;

Distance between two points : √[(x2 - x1)² + (y2 - y1)²]

Distance between R and S :

R = (-3,2)

S(2,2)

√[((2 - (-3))^2 + (2 - 2)^2]

Sqrt(5^2 + 0^2)

D1 = 5 units

Distance between S and T:

S(2,2)

T(2,-5).

D2 = √[(2 - 2)^2 + (-5 - 2)^2]

D2 = sqrt(0^2 + (-7)^2)

D2 = 7 units

Hence, total length = D1 + D2 = (5 + 7) = 12 units

5 0
2 years ago
a projectile is thrown upward so that it's distance above the ground after T seconds is H equals -16t^2 + 672 T. After how many
Arada [10]

Step-by-step explanation:

T = time in seconds

H = distance

Tground = time to return to ground

Tmax = time at maximum height

H = -16T^2 + 672T...eqn 1

projectile returns to ground at H =0,

subs for H in eqn 1...

0 = -16T^2 + 672T

solving for T we get...

16T^2 = 672T

=> Tground = 42secs

Tmax = 0.5 Tground = 21secs

4 0
2 years ago
Please help, need help asap!
cluponka [151]
The correct answer is letter C
5 0
3 years ago
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