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kap26 [50]
3 years ago
11

What is q+5/9=1/6 what is q

Mathematics
2 answers:
Basile [38]3 years ago
8 0
Q is -7/18

Find least common denominator of 9 and 6 which is 18

Multiply by LCM=18
Q x 18 + 5/9 x 18= 1/6 x 18

Refine
18q + 10=3

Subtract 10 from both sides
18q+10-10=3-10

Refine
18q=7

Divide 18 by both sides
18q/18= -7/18

Refine
Q is -7/18

Eduardwww [97]3 years ago
5 0
If your teacher do not put the value of the q all the letters will be 1 so: 1+5=6 (after you just simplify)
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Solve the equations. 2.5x−3.67=1.52
aleksklad [387]
Our current equation is:
2.5x -3.67 = 1.52.
To solve for x, we need to get x by itself and then simplify what we can from there.
2.5x -3.67 = 1.52
Add 3.67 to both sides to get 2.5x by itself.
2.5x = 5.19 is now our new equation.
Divide both sides by 2.5 to get x.
5.19/2.5 = 2.07
x = 2.07
I hope this helps!
5 0
3 years ago
How do you multiply mixed numbers with fractions
Vaselesa [24]

Answer:

Step-by-step explanation:

You first turn the mixed number into an improper fraction by mutliplying the denominator by the whole number then adding the numerator to the product. Make sure to keep the denominator the same and just put the sum as the numerator. Then, you multiply the fractions and simplify your answer! Hope this helped!

4 0
3 years ago
Read 2 more answers
Solving one to two step equations . algebra 1 .
frozen [14]

Answer:

1.) k = 5

2.) n = -20

3.) p = -13

4.) m = -450

5.) b = -38

6.) n = -24

7.) x = 21

8.) x = 12

9.) b = -2

10.) b = 5

Step-by-step explanation:

To solve all equations, do the reciprocal, or opposite of what is being done. For example, if a number and a variable are being multiplied, you would divide by the number to solve.

1.) 55 = 11k

(11 and k are being multiplied, so you would divide)

Divide by 11 on both sides:

55 = 11k

/11     /11

5 = k

2.) Add 15 on both sides:

n - 15 = -35

   +15    +15

n = -20

3.) Divide by -6 on both sides:

78 = -6p

/-6    /-6

-13 = p

4.) Multiply by 18 on both sides:

m/18 = -25

18(m/18) = (-25)18

m = -450

5.) Add 20 on both sides:

18 = -20 - b

+20  +20

38 = -b

Divide by -1 on both sides:

38 = -b

/-1     /-1

-38 = b

6.) Subtract 12 on both sides:

12 + n/4 = 6

-12            -12

n/4 = -6

Multiply by 4 on both sides:

4(n/4) = (-6)4

n = -24

7.) Multiply by 2 on both sides:

2(-7 + x/2) = (7)2

-7 + x = 14

Add 7 on both sides:

-7 + x = 14

+7         +7

x = 21

8.) Subtract 2 on both sides:

-4x + 2 = -22

      -2     -2

-4x = -24

Divide by -4 on both sides:

-4x = -24

/-4     /-4

x = 12

9.) Add 9 on both sides:

7 = -8b - 9

+9         +9

16 = -8b

Divide by -8 on both sides:

16 = -8b

/-8   /-8

-2 = b

10.) Multiply by -3 on both sides:

-3(b - 14/-3) = (3)-3

b - 14 = -9

Add 14 on both sides:

b - 14 = -9

  +14    +14

b = 5

3 0
3 years ago
If a single card is drawn from a standard 52-card deck, what is the probability that it is an ace or a spade?
klasskru [66]

A 52-card deck is made up of an equal number of diamonds, hearts, spades, and clubs. Because there are 4 suits, there is a 1/4 chance to draw one of them, in our case, spades.

There are 4 aces in a 52-card deck, so the chance of drawing one is 4/52, or 1/13.

The question asks for the probability of drawing an ace or a spade. Because it uses the word "or," we add the probabilities together. This is because there is a chance of drawing either of the cards; it doesn't have to meet both requirements to satisfy the statement.

However, if the question were to say "and," we would multiply the two probabilities.

Let's add 1/4 and 1/13. First, we can find a common denominator. We can use 52 because both fractions can multiply into it (since the ratio came from a deck of 52 cards as well).

\frac{1}{4} -- > \frac{13}{52}

\frac{1}{13} -- > \frac{4}{52}

Now we can add them together.

\frac{13}{52} + \frac{4}{52} = \frac{13+4}{52} = \frac{17}{52}

This cannot be simplified further, so the probability is 17 in 52, or 33%.

hope this helps!

7 0
1 year ago
Read 2 more answers
-7 pertenece a números racionales y el por qué
zhannawk [14.2K]
Cada número que puede expresarse como una razón de dos enteros, cuyo denominador es distinto de cero, se llama un número racional.

espero que esto ayude :)
3 0
3 years ago
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