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liq [111]
3 years ago
14

What is 36x - 8y^2 when x=3 and y=-6?

Mathematics
1 answer:
max2010maxim [7]3 years ago
3 0

Answer:

-180

Step-by-step explanation:

Substitute each number in and get 36(3) - 8(-6)^2

Simplify for -180

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4(3xy^4)^3/(2x^3y^5)^4
myrzilka [38]

Answer:

\frac{4\left(3xy^4\right)^3}{\left(2x^3y^5\right)^4}=\frac{27}{4x^9y^8}

Step-by-step explanation:

Given the expression

\:\:\frac{4\left(3xy^4\right)^3}{\left(2x^3y^5\right)^4}

solving the expression

\:\:\frac{4\left(3xy^4\right)^3}{\left(2x^3y^5\right)^4}=4\cdot \:\frac{\left(3xy^4\right)^3}{\left(2x^3y^5\right)^4}

             =4\:\frac{27x^3y^{12}}{16x^{12}y^{20}}

              =4\cdot \frac{3^3}{2^4x^9y^8}

The multiply fractions are defined as

\:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}

so the expression becomes

                =\frac{3^3\cdot \:4}{2^4x^9y^8}

                =\frac{3^3\cdot \:2^2}{2^4x^9y^8}

                =\frac{3^3}{2^2x^9y^8}

Refining

                 =\frac{27}{4x^9y^8}

Therefore,

\frac{4\left(3xy^4\right)^3}{\left(2x^3y^5\right)^4}=\frac{27}{4x^9y^8}            

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3 years ago
Course Home
kolbaska11 [484]

Answer:

........... .........

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3 years ago
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