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Dmitry_Shevchenko [17]
3 years ago
12

Help me plz im stuck

Mathematics
1 answer:
viva [34]3 years ago
7 0

Answer:

A) Fill the blanks, Fail, 0.15, Success, 244, 0.61

B) 240 times

Step by-step explanation:

A) Void , 96, 0.24

    Fail, 60, it should be 0.15 because 60/400

     Success, 400 - 96- 60 or 244 and the relative frequency is 0.61.

B)    

There is a total of 1000. If the relative frequency is 0.24, multiply 0.24 by 1000 to get the amount of times YOU would expect to be VOID.

Or in other words , 240 times

By proving it add all up

0.24 x 1000 + 0.76 x 1000 = 1000

<h3><u><em>Hope this helps!!!</em></u></h3><h3><u><em>PLEASE GIVE BRAINLIEST!!!</em></u></h3><h3><u><em>APPRECIATE IT!!!</em></u></h3><h3><u><em>AND AS ALWAYS,</em></u></h3><h3><u><em>SIMPLIFY BANANAS              : )</em></u></h3>

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A company sells widgets. The amount of profit, y, made by the
vfiekz [6]

Answer:

846.06 units

Step-by-step explanation:

The amount of profit, y, made by the  company, is related to the selling price of each widget, x, by the given  equation as follows :

y = -4x^2 + 183x- 1247 ...(1)

We need to find out the maximum amount of profit  the company can make.

For maximum profit put dy/dx = 0

So,

\dfrac{d}{dx}(-4x^2 + 183x- 1247)=0\\\\-8x+183=0\\\\x=\dfrac{183}{8}\\\\x=22.87

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y = -4(22.87)^2 + 183(22.87)- 1247\\\\=846.06

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4 0
3 years ago
9. A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?
SSSSS [86.1K]

Answer:

Part 4) r=84\ units

Part 9) sin(\theta)=-\frac{\sqrt{5}}{3}

Part 10) sin(\theta)=-\frac{9\sqrt{202}}{202}

Step-by-step explanation:

Part 4) A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

we know that

The circumference of a circle subtends a central angle of 360 degrees

The circumference is equal to

C=2\pi r

using proportion

\frac{2\pi r}{360^o}=\frac{56\pi}{120^o}

simplify

\frac{r}{180^o}=\frac{56}{120^o}

solve for r

r=\frac{56}{120^o}(180^o)

r=84\ units

Part 9) Given cos(∅)=-2/3 and ∅ lies in Quadrant III. Find the exact value of sin(∅) in simplified form

Remember the trigonometric identity

cos^2(\theta)+sin^2(\theta)=1

we have

cos(\theta)=-\frac{2}{3}

substitute the given value

(-\frac{2}{3})^2+sin^2(\theta)=1

\frac{4}{9}+sin^2(\theta)=1

sin^2(\theta)=1-\frac{4}{9}

sin^2(\theta)=\frac{5}{9}

square root both sides

sin(\theta)=\pm\frac{\sqrt{5}}{3}

we know that

If ∅ lies in Quadrant III

then

The value of sin(∅) is negative

sin(\theta)=-\frac{\sqrt{5}}{3}

Part 10) The terminal side of ∅ passes through the point (11,-9). What is the exact value of sin(∅) in simplified form?    

see the attached figure to better understand the problem

In the right triangle ABC of the figure

sin(\theta)=\frac{BC}{AC}

Find the length side AC applying the Pythagorean Theorem

AC^2=AB^2+BC^2

substitute the given values

AC^2=11^2+9^2

AC^2=202

AC=\sqrt{202}\ units

so

sin(\theta)=\frac{9}{\sqrt{202}}

simplify

sin(\theta)=\frac{9\sqrt{202}}{202}

Remember that      

The point (11,-9) lies in Quadrant IV

then      

The value of sin(∅) is negative

therefore

sin(\theta)=-\frac{9\sqrt{202}}{202}

5 0
3 years ago
Can someone help me
V125BC [204]

Answer in attachment.

4 0
3 years ago
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