In the given question, one important information for getting to the actual solution is not given and that is the atmospheric pressure. To find the approximate absolute pressure, it is needed to add the value of atmospheric pressure with the gage pressure.
Atmospheric pressure = 100 kPa
Then
Absolute pressure = 156 + 100 kPa
= 256 KPa.
Answer:
18 V
Explanation:
The 3Ω resistor and the 6Ω resistor are in parallel, so the voltage difference across them is equal.
V = IR
V = (2 A) (3 Ω)
V = 6 V
So the current going through the 6Ω resistor is:
V = IR
6 V = I (6 Ω)
I = 1 A
Therefore, the current going through the 4Ω resistor is the sum:
I = 2 A + 1 A
I = 3 A
The voltage drop across the 4Ω resistor is:
V = IR
V = (3 A) (4 Ω)
V = 12 V
So the total voltage difference between K and L is:
V = 6 V + 12 V
V = 18 V
Answer:
more speed means that an object has more energy, now if an object's place is something such as a hill, the potential energy will increase meaning an object will have more speed and acceleration. this is because you have the earth's gravity helping you out when the object goes downhill, giving it the higher potential energy
The metals are the elements that more easily can lose electrons to fill their outermost shell. And among the metals the alkalyne are most likely than alkalyne earth and these are most likely than other metals.
As less electrons the metal has in its outermost shell the more likely it will lose an electron fo fill its outermost shell.
So, Li, Na, K, Rb, Cs, and Fr have one electron in their outermost shell, so they are more likely to lose an electron to fill their outermost shell than Be, Mg, Ca, Sr, Ba, Ram which have two electrons in their outermost shell.
Using the same reasoning, Be, Mg, Ca, Sr, Ba, Ra are more likely to lose an electron to fill its outermost shell than Al, Ga, In, Tl.
Al, Ga, In, Tl are more likely to lose an electron than Si, Ge, Sn, Pb.
Si, Ge, Sn, Pb are more likely to lose an electron than O, S, Se, Te, Po
O, S, Se, Te, Po are more likely to lose an electron than F, Cl, Br, I, At
F, Cl, Br, I, At (halogens) and He, Ne, Ar, Kr, Xe, Rn (noble gases) will not likely lose electrons.