Answer:
Step-by-step explanation:
EH=w
then it is as simple as pluggin in
gh=4(eh)-51
Answer:
The length of the altitude is 9.3 yards and
The area of the triangle Δ UVW is 139.3 yd².
Step-by-step explanation:
Given
WU = 22 yd
WV = 30 yd
∠ UWV = 25°
To Find:
Altitude, UM = ?
area of the Δ UVW = ?
Construction:
Draw UM perpendicular to WV, that is altitude UM to WV.
Solution:
In right triangle Δ UWM if we apply Sine to angle W we get
substituting the values we get
Therefore, the altitude from U to WV is UM = 9.3 yd.(rounded to nearest tenth)
Now for area we have formula
The area of the triangle Δ UVW is 139.3 yd². (rounded to nearest tenth)
12b+36c+33 Should be the answer you just multiply each number in the parentheses by 3
Answer:
The temperature of the solution after 3 hours rounded to the nearest whole degree is -6 C
Step-by-step explanation:
From the question, the temperature of the chemical solution at the start of the experiment is -14.96 C.
Now, if the temperature increases by 2.9 C each hour,
Then, after 3 hours, the temperature of the chemical solution would have increased by
2.9 C/h × 3 h
8.7 C
Hence, the temperature of the chemical solution would have increased by 8.7 C after 3 hours.
The temperature of the chemical solution after 3 hours will be
-14.96 C + 8.7 C
= -6.26 C
≅ -6 C (to the nearest whole degree)
She got approximately 1.67 pounds of sugar per dollar. Please mark brainliest it would greatly be appreciated.
