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Tanzania [10]
3 years ago
12

I need help is it A B C or D

Mathematics
2 answers:
BARSIC [14]3 years ago
8 0
It's A
Subtract 10 from both sides and you get y=-x-1
lana [24]3 years ago
3 0
I'm thinking b
or c is what i think hope i could help ^-^

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ikadub [295]

Answer:

chicken nuggies

Step-by-step explanation:

4 0
2 years ago
Please answer the question from the attachment.
Zolol [24]
1.  30.25
2. 81
3. Square Root of 2 plus 1, Negative Square Root of 2  plus 1.
4. Square Root of 57 minus 3, Negative Square root of 57 minus 3
5. Square Root of 53.25 minus 11, Negative Square root of 53.25 minus 11



3 0
3 years ago
Subtract- a(b-5) from b(5-a)
TiliK225 [7]

Answer:

5b - 5a

Step-by-step explanation:

b(5 - a) = 5b - ab

- a(b - 5) = - ab + 5a

Subtracting gives

5b - ab - (- ab + 5a) ← distribute parenthesis by - 1

= 5b - ab + ab - 5a ← collect like terms

= 5b - 5a

3 0
3 years ago
What is half of pi/3?
Alborosie
Half of pi/3 means 1/2 times pi/3=pi/6
5 0
3 years ago
One of our brainliest, Konrad509, made this:
Reil [10]

\dfrac{B_x \sqrt{74_x}}{1D_x}+J_x51_x=4G3_x

A=10, B=11, C=12, etc.

\dfrac{11\cdot x^0\cdot \sqrt{7\cdot x^1+4\cdot x^0}}{1\cdot x^1+13\cdot x^0}+19\cdot x^0\cdot (5\cdot x^1+1\cdot x^0)=4\cdot x^2+16\cdot x^1+3\cdot x^0\\\\\dfrac{11\sqrt{7x+4}}{x+13}+19(5x+1)=4x^2+16x+3\\\\\dfrac{11\sqrt{7x+4}}{x+13}+95x+19=4x^2+16x+3\\\\11\sqrt{7x+4}+95x(x+13)+19(x+13)=(4x^2+16x+3)(x+13)\\\\11\sqrt{7x+4}+95x^2+1235x+19x+247=4x^3+52x^2+16x^2+208x+3x+39\\\\11\sqrt{7x+4}=4x^3-27x^2-1043x-208\\\\121(7x+4)=(4x^3-27x^2-1043x-208)^2

121(7x+4)=(4x^3-27x^2-1043x-208)^2\\\\847x+484=16 x^6 - 216 x^5 - 7615 x^4 + 54658 x^3 + 1099081 x^2 + 433888 x + 43264\\\\16 x^6 - 216 x^5 - 7615 x^4 + 54658 x^3 + 1099081 x^2 + 433041 x +42780=0

Now, the "only" thing that remains to do is solving the above equation.

While making this problem I only made sure it has a solution. I didn't try to solve it myself and I didn't know it will end up with such "convoluted" polynomial. Sorry to everyone who tried to solve it... m(_ _)m

I think the best way to approach it is using the rational root theorem since we know that x\in\mathbb{N}. Moreover we can deduce that x\geq19 since there is J and J=19.

After you succesfully solve it, you should get the answer x=20.

7 0
4 years ago
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