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Damm [24]
3 years ago
7

Subtract- a(b-5) from b(5-a)

Mathematics
1 answer:
TiliK225 [7]3 years ago
3 0

Answer:

5b - 5a

Step-by-step explanation:

b(5 - a) = 5b - ab

- a(b - 5) = - ab + 5a

Subtracting gives

5b - ab - (- ab + 5a) ← distribute parenthesis by - 1

= 5b - ab + ab - 5a ← collect like terms

= 5b - 5a

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Genrish500 [490]
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60÷100 =0.6
0.6×45 = 27
7 0
3 years ago
CAN YALL PLEASE WORK IT OUTTT <br><br> $18.79 + $2.11 + ‐$1.92 + $17.28
Dmitry [639]

Answer:

40.1

Step-by-step explanation:

Because the order of operations (Bodmas or Pedmas) tells you to add from left to right. So you would do 18.79 + 2.11 = 20.9, then you would do 20.90 + 1.92 (Add 0 at the end of 20.9) = 22.81. Then you will add 22.81 + 17.28 = 40.1. So your answer is 40.1. Hope this helps!

7 0
1 year ago
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Igoryamba

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20

25

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40

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Step-by-step explanation:

YOUR WELCOME (this too forever pls name me brainliest)

6 0
3 years ago
Read 2 more answers
Two step equation 7x - 24 = 25 i really need help with this
nekit [7.7K]

Answer:

x = 7

Step-by-step explanation:

move all terms that don't contain x to the right side and solve :)

6 0
2 years ago
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Which expression is equivalent to *picture attached*
Sedbober [7]

Answer:

\sum_{n=3}^{20}(n(n+1))=\sum _{n=3}^{20} n^2+ \sum _{n=3}^{20} n

Step-by-step explanation:

Given expression : \sum_{n=3}^{20}(n(n+1))

Solving further :

\Rightarrow \sum_{n=3}^{20}(n^2+n)

\Rightarrow \sum _{n=3}^{20} n^2+ \sum _{n=3}^{20} n

So, \sum_{n=3}^{20}(n(n+1))=\sum _{n=3}^{20} n^2+ \sum _{n=3}^{20} n

So, The given expression is equivalent to Option A

So, Option A is the answer

7 0
3 years ago
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