Answer:
She will pay $216 if she uses the coupon.
Step-by-step explanation:
Since the coupon is 1/7 off, you do 1/7 * 252 = 36. So she saves $36 with the coupon. Subtract the coupon from the total purchase. $252 - $36 = $216.
Answer:
3.25 miles
Step-by-step explanation:
Combine the total laps by doing 6 + 7 to get 13. Then, multiple 13 by 0.25 to get your sum of 3.25 miles.
Technically it would be 61 because 60 (numbers of cars) times 5 (fee per car) = 300 so at 61 he would be makings more in fees than his fixed salary
B=y=-x/2-1 <span>(-6,2). When x of the line is -6, y of the line must be 2.</span>Because you said the line passes through this point, right?
Now, look at our line's equation so far: . b is what we want, the -1/2 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (-6,2).
So, why not plug in for x the number -6 and for y the number 2? This will allow us to solve for b for the particular line that passes through the point you gave!.
<span>(-6,2). y=mx+b or 2=-1/2 × -6+b, or solving for b: b=2-(-1/2)(-6). b=-1.</span>
Step-by-step explanation:
Let S be the sample space
S={HH, HT, TH, TT}
n(S)= 4
A: both the coins with some place
B: both the coins with different place
C:at least one tail
D:at the most one head
1) A={TT,HH}
n(A)=2
P(G)= n(A)/n(S)
= 2/4
= 1/2
2) B ={HT, TH}
n(B) = 2
P(B) = n(B)/n(S)
= 2/4
= 1/2
3) C= {HT, TH, TT}
n(C)=3
P(C) = n(C)/n(S)
= 3/4
4). D={HT, TH}
n(D) = 2
P(D) = n(D)/n(S)
= 2/4
=1/2