3.)
Variables:
New tablet cost (575),
Money already saved, (56),
Money saved per week(14w)
Write an Equation:
The amount of weekly money you need to earn must cover the leftover cost needed to buy the tablet, therefore:
money_needed - money_you_have = money_earned_per_week
575 - 56 = 14w
Solving:
575 - 56 = 14w
519 = 14w
37.071428 = w
37 weeks needed
You solve the other two on your own.
Answer:
The solution for the system of linear equations 3x-y=10 and 2x+y=5 is x=3 y= -1
<u>Solution:
</u>
Given that two linear equations are 3x-y = 10 and 2x + y = 5
We have to find the values of “x” and “y”
Let us consider 3x – y =10 ---- eqn 1
2x + y = 5 --- eqn 2
From eqn 1 , rearranging the terms we get
y = 3x-10 --- eqn 3
By substituting the value of “y” from eqn 3 into eqn 2 we get,
2x + 3x – 10 = 5
On solving above expression, 5x – 10 = 5
5x = 15
x = 3
Substitute the value of “x” in eqn 1 to obtain “y” value
3(3) – y = 10
9 – y = 10
y = 9-10 = -1
Hence the solution for the system of linear equations 3x-y=10
and 2x+y=5 is x=3 and y= -1
Answer:
1.) 3/4
2.) 44/5 or 8 4/5
3.) 17/6 or 2 5/6
Step-by-step explanation:
1.) 5/16 ÷ 5/12
To divide a fraction by another fraction, reciprocate (put the numerator to denominator and vice versa) the divisor then change the sign to multiplication:
5/16 × 12/5
5 × 12 / 16 × 5
Cancel out 5 since both numerator and denominator has it:
12 / 16
Divide both by 4:
12 ÷ 4 / 16 ÷ 4
3/4
2.) 3 1/5 • 2 3/4
You have to convert the fractions first to improper fractions by multiplying the denominator to the whole number then adding the numerator to the product:
3 1/5 = 3×5 + 1 = 16/5
2 3/4 = 2 × 4 + 3 = 11/4
Now you can multiply the numerator to numerator then denominator to denominator:
Since 16 is a factor of 4, you can cancel it out, which leaves 4:
16 / 5 × 11/4
4 × 11 / 5 × 1
44/ 5
3.) 6 3/8 ÷ 2 1/4
Convert to improper fraction:
6 3/8 = 6× 8 + 3 = 51/8
2 1/4 = 4 × 2 + 1 = 9/4
(51 × 4)/ (9×8)
51 × 1/ 9× 2
51 / 18
Divide by 3:
17/6
Because 140 divided by 16 is 8.75
Three fourths is 0.75 in decimal form
Answer:
Option 4) 
Step-by-step explanation:
we know that
If two figures are similar then the ratio of its areas is equal to the scale factor squared
Let
z------> the scale factor
x-----> the area of the dilated rectangle
y----> the area of the original rectangle
so

we have


substitute and solve for x

