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azamat
3 years ago
5

A game is played as follows: a die numbered 1 to 6 is rolled. If the number 1 comes up, you get nothing. If the number 2, 3, or

5 comes up, you win $4. If the number 4 or 6 comes up, you lose $6.
True
False
Mathematics
2 answers:
Gala2k [10]3 years ago
6 0
Thats a statement... not a question.
Yuri [45]3 years ago
6 0
False, unless im putting too much thought into this question i would say you're losing 5 because that is the number in between 4 and 6. just like 4 is the number in between  3 and 5
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The value of X - Y such that the eight-digit number 7448X24Y is divisible by both 8 and 9 is 7

<h3>How to determine the distinct digits X and Y?</h3>

The eight-digit number is given as:

7448X24Y

Also, from the question

The number is divisible by 8 and 9

When a number is divisible by 8, then the last three digits of that number would be divisible by 8.

When a number is divisible by 9, the sum of the digits of the number would be divisible by 9.

So, we have:

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The possible value of Y from the above statement is 0

This is so because 240 is divisible by 8

The sum of the digits of the number would be divisible by 9.

This means that:

7 + 4 + 4 + 8 + X + 2 + 4 + Y = 29 + X + Y

Substitute 0 for Y

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29 + X + Y = 29 + X

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So, we have

29 + X = 36

Subtract 29 from both sides of the equation

X = 7

So, we have

X = 7 and Y = 0

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X - Y = 7 - 0

Evaluate the difference in the above equation

X - Y = 7

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1.5

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