Answer:
Fourth degree polynomial (aka: quartic)
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Work Shown:
There isnt much work to show here because we can use the fundamental theorem of algebra. The fundamental theorem of algebra states that the number of roots is directly equal to the degree. So if we have 4 roots, then the degree is 4. This is assuming that there are no complex or imaginary roots.
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If you want to show more work, then you would effectively expand out the polynomial
(x-m)(x-n)(x-p)(x-q)
where
m = 4, n = 2, p = sqrt(2), q = -sqrt(2)
are the four roots in question
(x-m)(x-n)(x-p)(x-q)
(x-4)(x-2)(x-sqrt(2))(x-(-sqrt(2)))
(x-4)(x-2)(x-sqrt(2))(x+sqrt(2))
(x^2-6x+8)(x^2 - 2)
(x^2-2)(x^2-6x+8)
x^2(x^2-6x+8) - 2(x^2-6x+8)
x^4-6x^3+8x^2 - 2x^2 + 12x - 16
x^4 - 6x^3 + 6x^2 + 12x - 16
We end up with a 4th degree polynomial since the largest exponent is 4.
He needs to play 23 more times. 785 / 35 = 23
He will have extra points but it will be enough to get the prize.
Answer:
b= -1/5
Step-by-step explanation:
Though a variable's sign changes when it is multiplied by -1, its absolute value does not. Therefore, we can eliminate the 1:
1/5+b=0
b+1-1/5=0-1/5
b+0/5= 0 -1/5
b=0 -1/5
and you have b= -1/5 as your answer
I think the answer might be 6p^2+3p-63
Answer:
-10xsquared-x+38
Step-by-step explanation:
so,
general eqn of quadratic equation is,
axsquared+bx+c=y
where,
x and y are exchanged by coordinates given in qn
1,64a-8b+c=0
2,4a-2b+c=0
or c=2b-4a
60a-6b=0
3,36a-6b+c=8
32a-4b=8
