Domain:
This function is a polynomial, i.e. a sum of powers of a variables, each with its coefficient. Polynomials are defined for every possible value of the variable, so the domain is the whole real number set: 
Range:
A polynomial of degree 2 represents a parabola. Since the leading coefficients, i.e. the coefficient of the term with highest degree, is positive (in this case, it's 3), the parabola is concave up. It means that it has a minimum, and it's unbounded from above. So, the range is something like
. To find the minimum, let's start with the "standard" parabola
, and transform it to the one of this exercise.
has minimum 0, and thus its range is
. When you multiply it times three, its shape narrows, but the range wont change:
. Finally, when you subtract 5, you shift everythin down 5 units. This transformation affects the range, since you have 
Image of -3:
To compute
, simply plug
in the formula:

Numbers associated with 43:
We want to see which x value we must choose to get a y value of 43. So, the equation is

First we set up an equation with the givens (slope and y intercept):
y = 2x -4
next plug in 6 for x.
y = (2x6) - 4
y = 12 - 4
And this will give us the value of y: 8.
Answer:
3 would be your y intercept
then from the point 0,0 put 2 in as slope
Step-by-step explanation:
First turn the equation into y=mx+b (slope-intercept form)
Which turns into y= -2x+3
in y=mx+b
m is slope and b is y intercept
3 would be your y intercept
then from the point 0,0 put 2 in as slope
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25.8 - 5 = 20.8
20.8 divide by 2.5 = 8.32
so it should be 8
For me it’s A not sure tho