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jeyben [28]
3 years ago
10

1. The thermal convection that drives plate motion is caused by

Physics
1 answer:
noname [10]3 years ago
6 0
Subduction I believe
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Who was the first person to describe the earth as a magnet
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William Gilbert

Explanation:

first described the Earth as a giant dipole magnet 400 years ago. But, as Rod Wilson recounts, he did far more than this.

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What is the magnitude of the kinetic frictional force
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The battery is made up of three 1.5 V cells.
IrinaVladis [17]

Answer: 4.5 V

Explanation:

Given

The voltage of each cell is 1.5 V

If they are connected end to end their potential added to give a higher potential i.e. 1.5+1.5+1.5=4.5 V

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What is this?<br> Picture
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Scientists want to place a 3400.0 kg satellite in orbit around Mars. They plan to have the satellite orbit at a speed of 2480.0
BaLLatris [955]

Answer:

Part a)

r = 6.96 \times 10^6 m

Part b)

F_g = 3.004 \times 10^3 N

Part c)

a = 0.88 m/s^2

Part d)

v = \frac{2480}{2} = 1240 m/s

Explanation:

Part a)

As we know that the orbital speed of the satellite is given as

v = 2480 m/s

now we will have

v = \sqrt{\frac{GM_{mars}}{r}}

now we have

M_{mars} = 6.4191 \times 10^{23} kg

R_{mars} = 3.397 \times 10^6 m

now we have

2480 = \sqrt{\frac{(6.67 \times 10^{-11})(6.4191 \times 10^{23})}{r}}

r = 6.96 \times 10^6 m

Part b)

Here force between mars and satellite is the gravitational attraction force which is given as

F_g = \frac{GM_{mars} m}{r^2}

F_g = \frac{(6.67\times 10^{-11})(6.4191 \times 10^{23})(3400)}{(6.96\times 10^6)^2}

F_g = 3.004 \times 10^3 N

Part c)

Acceleration of satellite is the ratio of gravitational force and mass of the satellite

a = \frac{F_g}{m}

a = \frac{3004}{3400}

a = 0.88 m/s^2

Part d)

As we know by III law of kepler

\frac{T_1^2}{T_2^2} = \frac{r_1^3}{r_2^3}

here we know that T2 = 8 T1

(\frac{1}{8})^2= \frac{r_1^3}{r_2^3}

\frac{r_1}{r_2} = (\frac{1}{2})^2

so we have

r_2 = 4r_1

as we know that speed is given as

v = \sqrt{\frac{GM}{r}}

so we can say since radius is orbit becomes 4 times so the orbital speed must be half

v = \frac{2480}{2} = 1240 m/s

7 0
4 years ago
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