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When a 4.25 kg object is placed on top of a vertical spring, the spring compresses a distance of 2.62 cm. what is the force cons

ANTONII [103]

The force applied to the spring is the weight of the object that compresses it, so it is equal to:
$W=mg=(4.25 kg)(9.81 m/s^2)=41.7 N$

Because of this force, the spring compresses by $x=2.62 cm=0.0262 m$ . Using Hook's law,
$F=kx$ ,
since we know the intensity of the force (the weight W) and the compression of the spring, x, we can find k, the spring constant:
$k= \frac{F}{x}= \frac{W}{x}= \frac{41.7 N}{0.0262 m} =1591.6 N/m$

6 0

3 years ago

The Ptolemaic model of the universe:

harkovskaia [24]

Answer:

The Ptolemaic model of the universe A) explained and predicted the motions of the planets with deferents and epicycles.

Explanation:

Ptolemy of Alexandria built an explanation of the observed movements of the planets that remained in force for thirteen centuries. Ptolemy proposed a model of the Universe with the Earth in the center. In the model, the Earth remains stationary while the planets, the Moon and the Sun describe complicated orbits around it. In other words, Ptolemy devised a system in which he used epicycles, deferential and eccentric, and it was necessary to introduce an equating point to reproduce planetary movements. He proposed that:

a) Each planet revolves with constant velocity around a circle called an epicycle.

b) The center of the epicycle is located and moves with constant velocity around another circle called deferential.

c) The center of the deferent is located at a moving point, which travels with constant speed describing another circumference called eccentric.

d) The center of the eccentric coincides with the center of the Universe.

e) Since the Earth is not located in the center of the Universe, but very close to it, it was necessary to introduce an equating point, which is not on Earth, and from which you can see the planet move with constant speed.

However, Ptolemy put forward this geometric theory to explain mathematically the movements and failed to adjust any system of cycles, epicycles and eccentrics that accurately represented the observed movements of the planets.

Finally, The Ptolemaic model of the universe A) explained and predicted the motions of the planets with deferents and epicycles.

8 0

2 years ago

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A transformer has a 240 V primary and a 60 V secondary. With a 5 ohm load connected, what is the primary current?

musickatia [10]

Answer:primary current is 3A

Explanation:

primary voltage Vp=240V

secondary voltage Vs=60V

resistance 5Ω

primary current in the circuit is

$I_{P} =I_{S} \frac{V_{S}}{V_{P}}\\I_{P} =\frac{V_{S}}{R} \frac{V_{S}}{V_{P}}\\I_{P}=\frac{60\times 60}{5\times 240\\}\\I_{P}=3 A$

4 0

3 years ago

A painter on a ladder, painting the ceiling of a room comments. “It is hotter up here by the ceiling than it is down on the floo

ira [324]

Answer:

1. Hot air is less dense and has moved upward allowing cool air to move downward which is less dens

(Convection current)

2. The ceiling has transferred heat to him by radiation.

Explanation:

During the day when air is heated as a result of the ceiling transferring heat to it, it becomes less dens and it gains energy, which make it lighter in weight than cooler air, this hot air moves upward allowing cooler air to move downward.

4 0

3 years ago

If F1 is the magnitude of the force exerted

aleksandrvk [35]

Answer: 3. F1 = F2

Explanation:

According to Newton's law of Gravitation, the force $F$ exerted between two bodies or objects of masses $M$ and $m$ and separated by a distance $r$ is equal to the product of their masses divided by the square of the distance:

$F=G\frac{Mm}{r^2}$ (1)

Where $G$ is the gravitational constant

Now, in the especific case of the Earth and the satellite, where the Earth has a mass $M$ and satellite a mass $m$ , being both separated a distance $r$ , the force exerted by the Earth on the satellite is:

$F1=G\frac{Mm}{r^2}$ (2)

And the force exerted by the satellite on the Earth is:

$F2=G\frac{Mm}{r^2}$ (3)

As we can see equations (2) and (3) are equal, hence the magnitude of the gravitational force is the same for both:

$F1=F2$

3 0

3 years ago