What is the magnitude of the kinetic frictional force
1 answer:
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Answer:
to overcome the out of friction we must increase the angle of the plane
Explanation:
To answer this exercise, let's propose the solution of the problem, write Newton's second law. We define a coordinate system where the x axis is parallel to the plane and the other axis is perpendicular to the plane.
X axis
fr - Wₓ = m a (1)
Y axis
N- = 0
N = W_{y}
let's use trigonometry to find the components of the weight
sin θ = Wₓ / W
cos θ = W_{y} / W
Wₓ = W sin θ
W_{y} = W cos θ
the friction force has the formula
fr = μ N
fr = μ Wy
fr = μ mg cos θ
from equation 1
at the point where the force equals the maximum friction force
in this case the block is still still so a = 0
F = fr
F = (μ mg) cos θ
We can see that the quantities in parentheses with constants, so as the angle increases, the applied force must be less.
This is the force that balances the friction force, any force slightly greater than F initiates the movement.
Consequently, to overcome the out of friction we must increase the angle of the plane
the correct answer is to increase the angle of the plane
Explanation:
Given that,
Terminal voltage = 3.200 V
Internal resistance
(a). We need to calculate the current
Using rule of loop
Where, E = emf
R = resistance
r = internal resistance
Put the value into the formula
(b). We need to calculate the terminal voltage
Using formula of terminal voltage
Where, V = terminal voltage
I = current
r = internal resistance
Put the value into the formula
(c). We need to calculate the ratio of the terminal voltage of voltmeter equal to emf
Hence, This is the required solution.