Ask question

Ask question

All categories

2 years ago

7

A supersized laundry detergent has 60% more detergent than the regular size. The supersized has 144 ounces. How many ounces of t

he detergent are in the regular size

1 answer:

Tems11 [23]2 years ago

6 0

26+144 ounces = 170 ounces

Step-by-step explanation:

144/60% or 144/6= 26

You might be interested in

HELP ASAP PLSSS TY TY TYY

Gnoma [55]

Answer:

c

Step-by-step explanation:

╰╮╰╮╰╮

╭━━━━━━━╮╱

╰━━━━━━━╯╱

┃╭╭╮┏┏┏┏┣━╮

┃┃┃┃┣┣┣┣┃╱┃

┃╰╰╯┃┃┗┗┣━╯

╰━━━━━━━╯

6 0

3 years ago

Pls send answer pls, I rlly need help thank you so much

shepuryov [24]

Try y=-2x-3 (I think that should be it)

6 0

3 years ago

Cl2 + 2KBr -> Br2 + 2KCl what is the reaction?

Serjik [45]

Answer:

Step-by-step explanation:

C

l

2

+

2

K

B

r

→

2

K

C

l

+

B

r

2

Given:

300

g

of

C

l

2

300

g

of

K

B

r

(a) Mass of

C

l

2

= 300g

Molecular mass of

C

l

2

= 2(35.45) = 70.906 g

/

m

o

l

No.of moles of

C

l

2

=

m

a

s

s

/

m

o

l

a

r

m

a

s

s

=

300

/

70.906

=

4.23

moles

Mass of

K

B

r

=

300

g

Molar mass of

K

B

r

=

39

+

79.9

=

118.9

g

/

m

o

l

No.of moles of

K

B

r

=

300

/

118.9

=

2.52

moles

Now,

Consider the equation:

C

l

2

+

2

K

B

r

→

2

K

C

l

+

B

r

2

1

mole of

C

l

2

= 2 moles of

K

C

l

4.23

moles of

C

l

2

= 2x4.23=

8.46

moles

2

moles of

K

B

r

= 2 moles of

K

C

l

2.52

moles of

K

B

r

=

2.52

moles

Now convert moles to mass,

Mass of

K

C

l

produced by

C

l

2

=

8.46

×

70.906

=

599.8

g

Mass of

K

C

l

produced by potassium bromide =

2.52

×

74.5

=

187.74

g

3 0

3 years ago

HELLOOOO HELP PLEASE

MA_775_DIABLO [31]

Answer:

$2*log(x)+log(y)$

Step-by-step explanation:

So, there are two logarithmic identities you're going to need to know.

<em>Logarithm of a power</em>:

$log_ba^c=c*log_ba$

So to provide a quick proof and intuition as to why this works, let's consider the following logarithm: $log_ba=x\implies b^x=a$

Now if we raise both sides to the power of c, we get the following equation: $(b^x)^c=a^c$

Using the exponential identity: $(x^a)^c=x^{a*c}$

We get the equation: $b^{xc}=a^c$

If we convert this back into logarithmic form we get: $log_ba^c=x*c$

Since x was the basic logarithm we started with, we substitute it back in, to get the equation: $log_ba^c=c*log_ba$

Now the second logarithmic property you need to know is

<em>The Logarithm of a Product</em>:

$log_b{ac}=log_ba+log_bc$

Now for a quick proof, let's just say: $x=log_ba\text{ and }y=log_bc$

Now rewriting them both in exponential form, we get the equations:

$b^x=a\\b^y=c$

We can multiply a * c, and since b^x = a, and b^y = c, we can substitute that in for a * c, to get the following equation:

$b^x*b^y=a*c$

Using the exponential identity: $x^{a}*x^b=x^{a+b}$ , we can rewrite the equation as:

$b^{x+y}=ac$

taking the logarithm of both sides, we get:

$log_bac=x+y$

Since x and y are just the logarithms we started with, we can substitute them back in to get: $log_bac=log_ba+log_bc$

Now let's use these identities to rewrite the equation you gave

$log(x^2y)$

As you can see, this is a log of products, so we can separate it into two logarithms (with the same base)

$log(x^2)+log(y)$

Now using the logarithm of a power to rewrite the log(x^2) we get:

$2*log(x)+log(y)$

3 0

1 year ago

A rectangle has a length of 12 mm and a width of 15 mm. A new rectangle was created by multiplying all of the dimensions by a sc

solmaris [256]

Answer:

the new perimeter will be 1/3 time the perimeter of the original rectangle

Step-by-step explanation:

8 0

3 years ago