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zmey [24]
3 years ago
15

Establish for which constants c the following function is a density.

Mathematics
1 answer:
Valentin [98]3 years ago
7 0
By "density" I assume you mean "probability density function". For this to be the case for f(x), we require

\displaystyle\int_{-\infty}^\infty f(x)\,\mathrm dx=1

Since

f(x)=\begin{cases}cx^{1/2}&\text{for }0

you have

\displaystyle\int_{-\infty}^\infty f(x)\,\mathrm dx=\int_0^2cx^{1/2}\,\mathrm dx=\dfrac{2c}3x^{3/2}\bigg|_{x=0}^{x=2}=\dfrac{2^{5/2}c}3=1

which means

c=\dfrac3{2^{5/2}}=\dfrac3{4\sqrt2}
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Step-by-step explanation:

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