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Kamila [148]
3 years ago
12

I need help with this asapp

Mathematics
1 answer:
Brrunno [24]3 years ago
8 0
Still need help? Let me know
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4x+7y=2<br> solve for x.
Kitty [74]

Subtract 7y7y from both sides

4x=2−7y

Divide both sides by 4

x= 2 - 7 y/ 4

     



7 0
3 years ago
Read 2 more answers
The average (arithmetic mean) of 12, 25, and x is 21. What is the value of x?
Dominik [7]
The answer is 26, the average is found by adding all the numbers and dividing by how there are. you are given 2 sets (25,12) and need to find X, the average should be 21. 25+12 is 37, 37+(c) which is 26 = 63 , you then divide 63 by how many numbers you had , which is 3 and the answer is 21.
4 0
3 years ago
What are the vertices of /(△)?
Serga [27]

Answer:

3!

Step-by-step explanation:

The vertices are the points of the triangle. So if you count each point you get 3!

8 0
3 years ago
Read 2 more answers
Prism A and prism B are similar with a ratio of similarity of 2:3. If the volume of prism A is 36 cubic units, what is the volum
kozerog [31]
Ratio of their
 x = 27*36 / 8 volumes = 2^3 : 3^3  or 8:27

so 8/27 = 36/x

x = 27*36 / 8 =  121.8 cubic units
5 0
4 years ago
A marketing study was conducted to compare the mean age of male and femlae purchasers of a certain product. random and independe
notka56 [123]

Answer:

A. t ≥ 1.734

Step-by-step explanation:

Data given and notation  

\bar X_{m}=39.80 represent the mean for the sample male

\bar X_{f}=50.30 represent the mean for the sample female

s_{m}=10.040 represent the sample standard deviation for the males  

s_{f}=13.215 represent the sample standard deviation for the females  

n_{m}=10 sample size for the group male  

n_{f}=10 sample size for the group female  

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the mean for females is higher than the mean for males, the system of hypothesis would be:  

Null hypothesis:\mu_{f}-\mu_{m}\leq 0  

Alternative hypothesis:\mu_{f} - \mu_{m}> 0  

We don't have the population standard deviation, so for this case is better apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{f}-\bar X_{m})-\Delta}{\sqrt{\frac{s^2_{f}}{n_{f}}+\frac{\sigma^2_{m}}{n_{m}}}} (1)

And the degrees of freedom are given by df=n_m +n_f -2=10+10-2=18  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

What is the test statistic?

With the info given we can replace in formula (1) like this:  

t=\frac{(50.3-39.80)-0}{\sqrt{\frac{13.215^2}{10}+\frac{10.040^2}{16}}}}=2.001

Critical value

For this case since we have a right tailed test we need to look into the t distribution with 18 degrees of freedom a value that accumulates 0.05 of the area on the right, and on this case:

t_{crit}=1.734

And the rejection zone of the null hypothesis would be: A. t ≥ 1.734

For our case our calculated value is higher than the critical value so we have enough evidence to reject the null hypothesis at the 5% of significance.

8 0
4 years ago
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