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2 years ago

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I need help with this asapp

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Brrunno [24]2 years ago

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Determine the slope of the following graph.

evablogger [386]

Answer:

2/1 or 2

Step-by-step explanation:

if you find a spot were the line is line up with the boxes in the graph like at (-2,0) up 2 and right one you will see the line is lined up again and since slope is rise/run its 2/1 or 2

4 0

2 years ago

HELP I need the know if it's going across the y or going across the x don't send no FILE ONLY ANSWER IF YOU REALLY KNOW question

baherus [9]

both the x and y line

7 0

2 years ago

Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y

irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

$y'(x)= x^2y(x)-\frac12y^2(x)$

Putting the value of y'(x) in equation (1)

$y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))$

Substituting x =0 and h= 0.2

$y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]$

$\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]$ [∵ y(0) =3 ]

$\Rightarrow y(0.2)\approx 2.7$

Substituting x =0.2 and h= 0.2

$y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]$

$\Rightarrow y(0.4)\approx 2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]$

$\Rightarrow y(0.4)\approx 1.9926$

Substituting x =0.4 and h= 0.2

$y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]$

$\Rightarrow y(0.6)\approx 1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]$

$\Rightarrow y(0.6)\approx 1.6593$

Substituting x =0.6 and h= 0.2

$y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]$

$\Rightarrow y(0.8)\approx 1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]$

$\Rightarrow y(0.6)\approx 0.8800$

Substituting x =0.8 and h= 0.2

$y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]$

$\Rightarrow y(1.0)\approx 0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]$

$\Rightarrow y(1.0)\approx 0.9152$

Therefore the value of y(1)= 0.9152.

4 0

3 years ago

When choosing a new class color, 90 students voted for crimson and 60 voted for royal blue. What percent of these students voted

neonofarm [45]

The percentage of students voted for colour crimson
=
$\frac{90}{60 + 90} \times 100\% \\ = \frac{90}{150} \times 100\%\\ = \frac{9}{15} \times 100\% \\ = 60\%$
hope it helps!

6 0

2 years ago

What is the equation of the line that passes through the point (-4,-2) and has a slope of -1/2

vampirchik [111]

Answer: y=-1/2x-4

Step-by-step explanation:

If you use point slope formula you get

y+2=-1/2(x+4)

simplify that in y=mx+b and you get

y=-1/2x-4

4 0

2 years ago