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Answer:
Step-by-step explanation:
Given: The radius of circle O is r, and the radius of circle X is r'.
To prove: Circle O is similar to circle X.
Proof: Move the center of the smaller circle onto the center of the largest circle. Translate the circle X by the vector XA onto circle O. The circles now have the same center.
A dilation is needed to increase the size of circle X to coincide with the circle O. A value which when multiplied by r' will create r.
The scale factor x to increase X:
⇒
A translation followed by a dilation with scale factor will map one circle to the other, thus proving the given both circles similar.
Therefore, circle O is similar to circle X.
Step-by-step explanation:
ANSWER
EXPLANATION
The given parallelogram has vertices,
L(0,-3), M(-2,1), N(1,5), O(3,1).
The diagonals of the parallelogram bisect each other.
From the diagram, we can see that, the diagonals have coordinates L(0,-3),N(1,5)
and
M(-2,1),O(3,1).
The midpoint of any of the diagonals will give us the coordinates of intersection of the diagonals.
Recall the midpoint formula,
Using L(0,-3),N(1,5) gives,
Or we could have also used,M(-2,1),O(3,1) to get,
The correct answer is C
EXPLANATION
The given parallelogram has vertices,
L(0,-3), M(-2,1), N(1,5), O(3,1).
The diagonals of the parallelogram bisect each other.
From the diagram, we can see that, the diagonals have coordinates L(0,-3),N(1,5)
and
M(-2,1),O(3,1).
The midpoint of any of the diagonals will give us the coordinates of intersection of the diagonals.
Recall the midpoint formula,
Using L(0,-3),N(1,5) gives,
Or we could have also used,M(-2,1),O(3,1) to get,
The correct answer is C