The answer is just use a calc lol 8
Answer:
3 is known as the power of 2.
ax² + bx + c = 0
x = (-b ± √(b² - 4ac))/2a
First, rewrite the first equation so that the first coefficient is 1. Divide everything by a.
(ax² + bx + c = 0)/a =
x² + (b/a)x + (c/a) = 0
Isolate (c/a) by subtracting (c/a) from both sides
x² + (b/a)x + (c/a) (-(c/a) = 0 (- (c/a)
x² + (b/a)x = 0 - (c/a)
Add spaces
x² + (b/a)x = -c/a
Take 1/2 of the middle term's coefficient and square it. Remember that what you add to one side, you add to the other.
x² + (b/a)x + (b/2a)² = -c/a + (b/2a)²
Simplify the left side of the equation.
x² + (b/a)x + (b/2a)² = (x + (b/2a))²
(x + b/2a))² = ((b²/4a²) - (4ac/4a²)) -> ((b² - 4ac)/(4a²))
Take the square root of both sides of the equation
√(x + b/2a))² = √((b²/4a²) - (4ac/4a²))
x + b/(2a) = (±√(b² - 4ac)/2a
Simplify. Isolate the x.
x = -(b/2a) ± (∛b² - 4ac)/2a = (-b ± √(b² - 4ac))/2a
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"Plainer headdresses and fewer neck-rings”“Belts hung with small crocodile heads”“The heads and shoulders of two tiny Europeans”
<u>Given</u>:
Given that the radius of the cone is 3 units.
The volume of the cone is 57 cubic units.
We need to determine the height of the cone.
<u>Height of the cone:</u>
The height of the cone can be determined using the formula,

Substituting the values, r = 3 and V = 57, we get;

Simplifying the terms, we get;

Multiplying both sides of the equation by 3, we get;


Dividing both sides of the equation by 28.26, we get;

Thus, the height of the cone is 6.05 units.