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o-na [289]
3 years ago
12

The function h(t)= -2(t-3)^2+23 represents the height, in feet, t seconds after a volleyball is served.Which of the following st

atements are correct
Mathematics
1 answer:
Tatiana [17]3 years ago
4 0

What are the statements?


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Solve the inequality. Graph the solution. Describe the graph in the area provided. Be sure to indicate where there is an open or
natka813 [3]

Step-by-step explanation:

The given inequality is :

-27\ge \dfrac{1}{2}(6x-12)

Solving RHS of the inequality:

-27\ge \dfrac{1}{2}\times 2(3x-6)\\\\-27\ge (3x-6)

Adding 6 both sides of the inequality

-27+6\ge (3x-6)+6\\\\-21\ge 3x\\\\x\le -7

The attached figure shows the graph for the given inequality.

7 0
3 years ago
Can you help me get the answer for <br> 1/3+1/4<br> plz
Ivahew [28]
7/12 is the answer :)
6 0
3 years ago
Read 2 more answers
Please help it's due today. Also please don't help if you don't know.​
zavuch27 [327]

Answer:

{x}^{16}  {y}^{22}

Step-by-step explanation:

multiple the top exponents by 3 and the u subtract the bottoms

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3 years ago
Solve 6 over x-3= 3 over x for x and determine if the solution is extraneous or not
polet [3.4K]
6/x-3=3/x
3x-9=6x
3x=-9
x=-3
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6 0
3 years ago
Help solve 4 and 5 please
Sloan [31]

Answer:

Step-by-step explanation:

4). a). If the diagonals of a parallelogram are congruent, then it must be a RECTANGLE.

b). If the diagonals of a parallelogram are perpendicular, then it must be a SQUARE.

c). If the diagonals of a parallelogram bisect the angles of the parallelogram, then it must be a RHOMBUS.

d). If the diagonals of a parallelogram are perpendicular and congruent, then it must be a SQUARE.

e). If a parallelogram has four congruent sides, then it must be a SQUARE.

5). Given quadrilateral SELF is a rhombus.

a). All sides of a rhombus are equal,

   Therefore, ES = EL = 25

b). Diagonals of a rhombus bisects the opposite angles,

   Therefore, m∠ELS = m∠FLS

    3x - 2 = 2x + 7

    3x - 2x = 7 + 2

    x = 9

c). Diagonals of the rhombus bisect the opposite angles, and adjacent angles are supplementary.

m∠ELF = 2(m∠ELS) = 2(2y - 9)

m∠LES = 2(m∠LEF) = 2(3y + 9)

And 2(2y - 9) + 2(3y + 9) = 180

(2y - 9) + (3y + 9) = 90

5y = 90

y = 18  

6 0
3 years ago
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