Question

A spring was at its resting position where it is attached to a wall at its left side and a block at its right side as shown below. The spring constant is k=75.0\,\dfrac{\text N}{\text m}k=75.0
m

N

​

k, equals, 75, point, 0, start fraction, start text, N, end text, divided by, start text, m, end text, end fraction. The block is moved leftwards and the spring's right end is displaced from the position of 0.250\,\text m0.250m0, point, 250, start text, m, end text to 0.150\,\text m0.150m0, point, 150, start text, m, end text where it is held in place. All positions are measured from the origin OOO of the wall.

Answer 1

Answer:

The force of spring will be "3.75 N". The further explanation is given below.

Explanation:

The given values are:

Spring constant, K = 75.0 N/m

x₁ = 0.200 m

x₂ = 0.150 m

So that,

⇒ $x=x_{1}-x_{2}$

⇒    $=0.200-0.15$

⇒    $=0.05 \ m$

Now,

Force of spring will be:

⇒  $F=K\times x$

On putting the estimated values, we get

⇒      $=75\times 0.05$

⇒      $=3.75 \ N$