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svet-max [94.6K]
3 years ago
14

Please Help me, Ive Been Stuck On This Question For Ages. :C (Image in question) (And Questions As Well)

Mathematics
1 answer:
MArishka [77]3 years ago
6 0
The answer is the third one.
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How do you decide where to place the first digit when you divide with greater number
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You place the first digit where you think it should go but mainly it goes here: on the top line of the division sign.

6 0
3 years ago
Which graph represents 2x-5y< 15
scoray [572]

Answer:

Step-by-step explanation:

Rewrite 2x-5y< 15 as follows:  Add 5y to both sides.  Then 2x < 15 + 5y.

Next, subtract 15 from both sides:  2x - 15 < 5y.

Finally, divide all terms by 5:           (2/5)x - 3 < y

Now find the y-intercept of this line.  Let x = 0.  Then y = -3.  Plot (0, -3) on graph paper.  Now, starting at (0, -3), move your pencil point 5 spaces to the right and 2 spaces up.  Plot this new point, (5, -1).  Now draw a dashed line through both (0, -3) and (5, -1).  Shade the area ABOVE this dashed line.

7 0
4 years ago
Evaluate this surd √50+√18-√98​
Dmitry [639]

.......the answer is 7.26

4 0
3 years ago
In a lake, there is a patch of lily pads. Every day, the patch doubles in size. If it takes 48 days for the patch to cover the e
ArbitrLikvidat [17]
See the plants grow in airthemetic progression.
day 1 its is 1 and day 2 it is 2, day 3 it is 4.......
so,
1,2,4,6,8,......
so it take 48 days to fill the pond..
total plants = 48/2(2*1+(48-1)*2)
total plants= 2304
so half the plants is 1152
so,
1152=n/2(2*1+(n-1)2)
n=47
it so 47 days to complete half the pond.
7 0
3 years ago
Read 2 more answers
Can somebody help me please?
kati45 [8]
 This is easy all you do to find the surface area is to multiply base the number that is across by the height the number that shows the height.The you just multiply those 2 and you got the surface area.For number one the answer is,20.For two the answer is, 6.Need more help ask me under in the comments. If this was helpful please give me brainiest answer. Hope this Helps :D
7 0
3 years ago
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