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IRINA_888 [86]
3 years ago
6

Write as a product of two polynomials. (x-y)^2-a(y-x)

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
3 0

Answer:

(x-y) (a+x-y)

Step-by-step explanation:

(y-x)=-(x-y)

-a(y-x) = a(x-y)

(x-y)^2 = (x-y)(x-y)

(x-y)(a + x - y)

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Part of a regression output is provided below. Some of the information has been omitted.
quester [9]

Answer:

301.189

Step-by-step explanation:

Given the table :

Source of Variation - - SS - - - df - - - MS - - - - F

Regression - - - - - -3177.17 - - -2 - - 1588.6

Residual - - - - - - - - ______ --17 - - -17.717

Total - - - - - - - - - - 3478.36 - - 19

Calculate the SSR, Sum of Square residual

The Sum of Square RESIDUAL (SSR), Mean Square Residual (MSR) and Degree of Freedom RESIDUAL (DFR) are related by the formular :

MSR = SSR / DFR

Hence,

SSR = MSR × DFR

Fr the table ;

MSR = 17.717 ; DFR = 17

SSR = (17.717 × 17)

SSR = 301.189

5 0
3 years ago
Please help by tomorrow ​
tigry1 [53]

Answer:

A: y = -2x + 2

B: 1100

Step-by-step explanation:

6 0
2 years ago
Sam used 6 loaves of elf bread on a 8 day hiking trip. He wants to know how many loaves of elf bread he should pack for a 12 day
KonstantinChe [14]
If he eats 6 loaves in 8 days, that means he ate 0.75 of a loaf each day. (6 divided by 8 = 0.75)
In a 12 day trip,
# divided by 12 = 0.75;
so to undo division, you multiply.
12 x 0.75 = #
# = 9. So 9 loaves for 12 days.
5 0
3 years ago
A random survey of 1000 students nationwide showed a mean ACT score of 21.1. Ohio was not used. A survey of 500 randomly selecte
vodka [1.7K]

Answer:

We conclude that the mean Ohio score is below the national average.

Step-by-step explanation:

We are given that a random survey of 1000 students nationwide showed a mean ACT score of 21.1. Ohio was not used.

A survey of 500 randomly selected Ohio scores showed a mean of 20.8. The population standard deviation is 3.

<u><em>Let </em></u>\mu<u><em> = mean Ohio scores.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 21.1      {means that the mean Ohio score is above or equal the national average}

Alternate Hypothesis, H_A : \mu < 21.1      {means that the mean Ohio score is below the national average}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about population standard deviation;

                    T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n}}}  ~ N(0,1)

where, \bar X = sample mean Ohio score = 20.8

            \sigma = population standard deviation = 3

            n = sample of Ohio = 500

So, <u><em>test statistics</em></u>  =  \frac{20.8-21.1}{\frac{3}{\sqrt{500}}}  

                              =  -2.24

The value of z test statistics is -2.24.

<em>Now, at 0.1 significance level the z table gives critical value of -1.2816 for left-tailed test.</em><em> Since our test statistics is less than the critical values of z as -2.24 < 1.2816, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><em><u>we reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that the mean Ohio score is below the national average.

4 0
3 years ago
By which theorem or postulate can the triangles be proven similar?
bogdanovich [222]
The answer is D hope it helps
8 0
3 years ago
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