I think we must use two numbers which have two digits and one of them must be one digited number.If we try it we can say our numbers are xy,ab and c.
xy + ab + c = 50
10x+y+10a+b+c = 50
10(x+a) + y+b+c = 50
Think about y+b+c. Maximum it can be 5+4+3 = 12 but it can't because there is a number which is multiple of 10.So it can be 10 maximum and x+a must be 4.
We can only use 1+3. 40 + y+b+c = 50 , y+b+c = 10. And other numbers are 2+4+5 = 11. 10 doesn't equal to 11 and it says there isn't any solution for this problem :)
Use Cymath to get your answer
Answer:
1/4
Step-by-step explanation:
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Answer: I really don't know how to do this sorry
Step-by-step explanation:
So first you want to draw out you triangle and label everything so side a would be x, side b would be 15 and c would be x
next the angles need to be label
and finally the anwser is 150m
