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zaharov [31]
2 years ago
14

The average life span of a lynx is

Mathematics
2 answers:
dangina [55]2 years ago
7 0

Answer:

20

Step-by-step explanation:

3/4 = 75%

15 ÷ 75% = 20

15 is 75% of 20.

Lynna [10]2 years ago
4 0

Answer:

3/15 years

Step-by-step explanation:

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Which shows the dimensions of two rectangular prisms that have volumes of
Alexxandr [17]
The answer is B 
volume of rectangular prism = (area* height )  
so 2 * 4 * 9 = 72 cm3 
   9* 4 * 2 = 72 cm3 
but they have differant surface area 
4 0
2 years ago
What is 416,000,000 expressed in scientific notation ?
Inga [223]
4.16 10^8


Hope this helps *smiles*
5 0
3 years ago
Which expression is equal to the expression below (6x9)^5
masha68 [24]

Answer:

B. You have to distribute properties. So you distribute the exponent 5 to both the 6 & the 9

4 0
3 years ago
Here are the monthly charges for Jo's mobile phone
yaroslaw [1]

Answer:

The correct answer is - 625.36.

Step-by-step explanation:

Given:

Fixed mothly plan - 616

free minutes - 150

Used minutes - 170

Free text - 150

Used text - 182

Charging amount over free limit - 18p

Solution:

Number of minutes over the limit -  170 - 150 = 20

Number of text over the limit - 182 - 150 = 32

So the extra amount that will be add to the monthly charge would be -

(20*0.18) +(32*0.18)

and the total charge of the month would be -

= 616+(20*0.18) +(32*0.18)

= 616+3.60+5.76

= 625.36

Thus, the correct answer would be - 625.36

5 0
3 years ago
The function f(x)=(x-5)^2 +2 is not one-to-one. Identify a restricted domain that makes the function one-to-one, and find the in
Anon25 [30]

We have been given a quadratic function f(x)=(x-5)^{2} +2 and we need to restrict the domain such that it becomes a one to one function.

We know that vertex of this quadratic function occurs at (5,2).

Further, we know that range of this function is [2,\infty).

If we restrict the domain of this function to either (-\infty,5] or [5,\infty), it will become one to one function.

Let us know find its inverse.

y=(x-5)^{2}+2

Upon interchanging x and y, we get:

x=(y-5)^{2}+2

Let us now solve this function for y.

(y-5)^{2}=x-2\\
y-5=\pm \sqrt{x-2}\\
y=5\pm \sqrt{x-2}\\

Hence, the inverse function would be f^{-1}(x)=5+\sqrt{x-2} if we restrict the domain of original function to [5,\infty) and the inverse function would be f^{-1}(x)=5-\sqrt{x-2} if we restrict the domain to (-\infty,5].

8 0
3 years ago
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