1130.97 is the surface area of the cylinder
Answer:
Option C
Step-by-step explanation:
In this case, an exponential function is a function that has common ratio whereas it is called a linear function if it has common difference.
Option A:
Since the values of y in the given table have different ratio but common difference, therefore it is not a a linear and not an exponential function. Option A is is not correct.
Option B:
Since the values of y in the given table have different ratio but common difference, therefore it is not a a linear and not an exponential function. Option B is not correct.
In option C.
Since the given values of y in the table have a common ratio, it is said to be an exponential function.
Option C is correct.
In option D.
Since the values of y in the given table have different ratio but common difference, therefore it is not a a linear and not an exponential function. Option D is incorrect.
Answer:
k=2
Problem:
if the equation x^2 +(k+2)x+2k=0 has equal roots,then the value of k is ..
Step-by-step explanation:
Since the coefficient of x^2 is 1, we can use this identity to aid us: x^2+bx+(b/2)^2=(x+b/2)^2.
So we want the following:
[(k+2)/2]^2=2k
Apply the power on the left:
(k+2)^2/4=2k
Multiply both sides by 4:
(k+2)^2=8k
Expand left side:
k^2+4k+4=8k *I used identity (x+c)^2=x^2+2xc+c^2
Subtract 8k on both sides:
k^2-4k+4=0
Factor using the identity mentioned a couple lines above:
(k-2)^2=0
Since zero squared is zero, we want k-2=0.
Adding both sides by 2 gives k=2.
Answer:
-2
Step-by-step explanation:
Answer:
a)5/9 yards=0.556yards
b)10/9 yards=1.11 yards
Step-by-step explanation:
for the part a
To solve this exercise we must divide the total distance traveled by the grasshopper (5 yards) by the number of jumps that were made (9).
if you use the calculator you will realize that the value is 0.55yards
for the part b
knowing the distance traveled in a jump, we multiply this value by two to find out how much is the distance traveled in 2 jumps
if you use the calculator you will realize that the value is 1.11 yards
