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Olin [163]
3 years ago
12

A square pyramid has a volume of 20 cubic units. What would be the change to the volume if the dimensions of the square base wer

e doubled?
Mathematics
2 answers:
Archy [21]3 years ago
7 0
The volume would be twice the original since the base area gets doubled. <span><span>13</span>×(BaseArea)×Height</span> Now, twice the Base Area would be : <span><span>13</span>×(2)(BaseArea)×Height</span><span> So, the entire thing gets doubled on the other side as well. Which means that 20 cubic units becomes 40 cubic units.</span>
Soloha48 [4]3 years ago
7 0

Answer:

The volume would be four times the original

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True

Step-by-step explanation:

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6 0
3 years ago
For each part of this problem, show all your work and write a probability statement.
AlladinOne [14]

Answer:

Follows are the answer to the given point.

Step-by-step explanation:

In point 1:

\to P( \text{number of response}) = \frac{192}{338} \\

                                        = \frac{96}{169}\\\\= 0.56

In point 2:

\to P| \text{(Zoloft and fill response)}| = \frac{27}{338}

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In point 3:

\to P(\frac{\text{ full or partial}}{\text{St. John's Wort}}) = \frac{\frac{43}{338}}{\frac{113}{338}}

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In point 4:

\to P(\frac{\text{Placebo}}{\text{full or response}}) = P(\frac{(\text{Placebo} \cap \text{full or response})} {\text{p(full response)}})

                               = \frac{\frac{79}{338}}{ 1- \frac{91}{338}} \\\\ = \frac{\frac{79}{338}}{  \frac{338-91}{338}} \\\\  = \frac{\frac{79}{338}}{\frac{247}{338}} \\\\  = \frac{79}{338} \times \frac {338}{247} \\\\= \frac{79}{274} \\\\ = 0.28

4 0
3 years ago
2. How many solutions does the below system of equations have?
bearhunter [10]
Y=5x-4

3y=15x-8
3(5x-4)=15x-8
15x-12=15x-8
??

Therefore, there is no solution.
8 0
3 years ago
Read 2 more answers
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