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Zina [86]
4 years ago
14

If f(x)=4-x^2 and g(x)=6x, which expression is equivalent to (g-f)(3)?

Mathematics
2 answers:
Inessa05 [86]4 years ago
6 0

Answer:

6(3) - 4 + 3^2

Step-by-step explanation:

We have (g-f)(x) = g(x) - f(x) because, that is how it is defined. Now, substituting g(x) and f(x) we obtain

(g-f)(x) = g(x) - f(x) = 6x - (4-x^2)

the minus sign is applied to everything inside the parenthesis

6x - (4-x^2) = 6x - 4 + x^2

and finally evaluating with x = 3, the result is

(g-f)(x) = 6(3) -4+ 3^2

nasty-shy [4]4 years ago
5 0

Answer:

see explanation

Step-by-step explanation:

Note that (g - f) = g(x) - f(x) = 6x - (4 - x²) = 6x - 4 + x²

(g - f)(3) = 6(3) - 4 + 3²

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Answer:

Step-by-step explanation:

[ (x + 7) / 6 ] − [ (x + 5) / (x + 3) ]

First, we must find the common denominator.  In this case, that's 6 (x+3).  Multiply the first fraction by (x+3)/(x+3) and the second fraction by 6/6.

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Now distribute the numerators:

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Now we combine the fractions:

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So the simplified form is:

\frac{x^{2} + 4x - 9}{6 (x + 3)}

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