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3 years ago

10

Ben's family left for vacation after his dad came home from work on Friday. The entire trip was 600 mi. Dad was

1 answer:

erastova [34]3 years ago

8 0

The dad had 6 more hours remaining to drive

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Sales fall from 300 per week to 270 per week what’s the percentage change

weeeeeb [17]

Hi there!

Your question:

Sales fall from 300 per week to 270 per week what's the percentage change?

My answer:

The formula for calculating percent change is as follows:

[(y2 - y1)/y1]*100=your percent change

y2= first value
y1=second value

Plug the numbers in:

[(300-270)/300]*100

[30/300]*100

0.1*100

10

Therefore, the percent change is 10%

Hope this helps! Let me know if it's incorrect so I can fix it:)

8 0

3 years ago

Solve for ? PLEASE HELP

schepotkina [342]

Answer:

70

Step-by-step explanation:

Tangent Chord Angle = 1/2Intercepted Arc

? = 1/2(140)

? = 70

6 0

3 years ago

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Mr. Allen has 2 dogs, Spike and Fido. He takes both of them outside at 6:00 a.m. He takes Spike outside every 3 hours. He takes

san4es73 [151]

Answer:

3 pm

Step-by-step explanation:

Because 3x5 = 15 and 5x3=15 so it would be at 3 pm

8 0

3 years ago

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PLEASE HELP!!!!!

kati45 [8]

The answer is 18.975 but you might want to round that to 18.98

4 0

4 years ago

Given csc(A) = 60/16 and that angle A is in Quadrant I, find the exact value of sec A in simplest radical form using a rational

Katarina [22]

Answer:

$\displaystyle \sec A=\frac{65}{63}$

Step-by-step explanation:

We are given that:

$\displaystyle \csc A=\frac{65}{16}$

Where <em>A</em> is in QI.

And we want to find sec(A).

Recall that cosecant is the ratio of the hypotenuse to the opposite side. So, find the adjacent side using the Pythagorean Theorem:

$a=\sqrt{65^2-16^2}=\sqrt{3969}=63$

So, with respect to <em>A</em>, our adjacent side is 63, our opposite side is 16, and our hypotenuse is 65.

Since <em>A</em> is in QI, all of our trigonometric ratios will be positive.

Secant is the ratio of the hypotenuse to the adjacent. Hence:

$\displaystyle \sec A=\frac{65}{63}$

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3 years ago

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