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grigory [225]
3 years ago
13

Which expression is equivalent -72x + 56

Mathematics
1 answer:
gogolik [260]3 years ago
4 0

The equivalent expression is 8(-9x + 7)

<em><u>Solution:</u></em>

Given that we have to write the equivalent expression

<em><u>Given expression is:</u></em>

-72x + 56

Let us write the equivalent expression by taking the greatest common factor out

When we find all the factors of two or more numbers, and some factors are the same, then the largest of those common factors is the Greatest Common Factor.

The factors of 56 are: 1, 2, 4, 7, 8, 14, 28, 56

The factors of 72 are: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72

Then the greatest common factor is 8

Thus factor out 8 from given expression

-72x + 56 = 8(-9x + 7)

Thus the equivalent expression is 8(-9x + 7)

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Step-by-step explanation:

Semicircle:

diameter  = length of the rectangle = 25 cm

Half circumference = πd/2

= 3.14 * 25/2 = 39.25 cm

Perimeter of the figure = 39.25 + 20 + 25 + 20

= 104.25 cm

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3 years ago
A box with a square base and open top must have a volume of 157216 cm3. We wish to find the dimensions of the box that minimize
shepuryov [24]

Answer:

  • Base Length of 68cm
  • Height of 34 cm.

Step-by-step explanation:

Given a box with a square base and an open top which must have a volume of 157216 cubic centimetre. We want to minimize the amount of material used.

Step 1:

Let the side length of the base =x

Let the height of the box =h

Since the box has a square base

Volume =x^2h=157216

h=\dfrac{157216}{x^2}

Surface Area of the box = Base Area + Area of 4 sides

A(x,h)=x^2+4xh\\$Substitute h=\dfrac{157216}{x^2}\\A(x)=x^2+4x\left(\dfrac{157216}{x^2}\right)\\A(x)=\dfrac{x^3+628864}{x}

Step 2: Find the derivative of A(x)

If\:A(x)=\dfrac{x^3+628864}{x}\\A'(x)=\dfrac{2x^3-628864}{x^2}

Step 3: Set A'(x)=0 and solve for x

A'(x)=\dfrac{2x^3-628864}{x^2}=0\\2x^3-628864=0\\2x^3=628864\\x^3=314432\\x=\sqrt[3]{314432}\\ x=68

Step 4: Verify that x=68 is a minimum value

We use the second derivative test

If\:A(x)=\dfrac{x^3+628864}{x}\\A''(x)=\dfrac{2x^3+1257728}{x^3}\\$When x=68\\A''(x)=6

Since the second derivative is positive at x=68, then it is a minimum point.

Recall:

h=\dfrac{157216}{x^2}\\h=\dfrac{157216}{68^2}=34

Therefore, the dimensions that minimizes the box surface area are:

  • Base Length of 68cm
  • Height of 34 cm.
3 0
3 years ago
Please help me! I’m so lost and don’t know where to start.
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Hope this helped :))
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