Center : Mean Before the introduction of the new course, center = average(121,134,106,93,149,130,119,128) = 122.5 After the introduction of the new course, center = average(121,134,106,93,149,130,119,128,45) = 113.9 The center has moved to the left (if plotted in a graph) because of the low intake for the new course. Spread before introduction of the new course : Arrange the numbers in ascending order: (93, 106,119, 121), (128, 130,134, 149) Q1=median(93,106,119,121) = 112.5 Q3=median(128,130,134,149) = 132 Spread = Interquartile range = Q3-Q1 = 19.5 After addition of the new course,
(45,93, 106,119,) 121, (128, 130,134, 149)
Q1=median(45,93,106,119)=99.5
Q3=median (128, 130,134, 149)= 132
Spread = Interquartile range = 132-99.5 =32.5
We see that the spread has increased after the addition of the new course.
Subtract the part from the total:
102.50 - 15 = 87.50
Now divide the remainder by rate:
87.50 / 25 = 3.5 hours
S = 3/5 or 0.6
explanation
-4/0.8 = 2/s-1
divide the numbers on the left: -5 = 2/s-1
multiply both side by s-1: -5(s-1)=2
simplify: -5s + 5 =2
gather like terms: -5s= 2 - 5
simplify: -5s= -3
divide both sides by -5: x=3/5
Given:
Aim:
We need to find the value of x.
Explanation:
Subtract 3 from both sides of the equation.
Divide both sides of the equation by 5.
Square both sides.
multiply
