Solution for part A is where the red line and the red line meet, (2,-1)
solution for part B: any point on the blue red line is a solution. (2, -1), (0, 3), (3, -3), (-2, 7)
solution for part C is where the green curve and the blue line meet, (0,3)
Its is surprising that no one attempted this question for over a week.
As in all geometry problems, start with a diagram (shown).
Then we realize right away that AB=sqrt(8^2+2^2)=sqrt(68)=2sqrt(17)
BC=sqrt(4^2+1^2)=sqrt(17)
The perimeter is therefore twice the sum of AB+BC=2(2sqrt(17)+sqrt(17))
2(3sqrt(17))=6 sqrt(17) We can estimate sqrt(17)=4.125, so 6sqrt(17)=24.75 which is close enough to get the correct answer choice.
Have a good day.
1. given
2. corresponding parts theorem
- segments AB and DB are similar
and segments BC and BE are also similar. lastly the circle at angles C and E indicate that they are congruent
3. SSA similarly theorem
AB and BC are similar and BC and BE are similar and angle C and E are congruent. also the triangles are not congruent in length so that makes them similar.
i apologize if i am incorrect i like just learned this. have a great day and good luck on your studies
Answer:
2
Step-by-step explanation:
Simplify 3y=6x+1;
y=2x-1/3
y=mx+b , where m represents the slope.
Slope; 2