Ask question

Ask question

All categories

3 years ago

15

The ratio of boys to girls in Mr. Baker’s social studies class is 2 to 3. If there are 30 total students in the class, how many

more girls are in the class than boys? A. 6 B. 8 C. 10 D. 12

2 answers:

nadya68 [22]3 years ago

4 0

A.6 the answer are A.6

kirill115 [55]3 years ago

4 0

c. 10

1. Multiply 3 by 10 to reach 30
2. Do the same for 2 and reach 20
3. 30-20 is 10

You might be interested in

3x + 7 = 9x + 3<br> No solution one solution or infinite

AlexFokin [52]

Answer:

One solution.

Step-by-step explanation:

X=2/3 or x=2.6666

4 0

3 years ago

Read 2 more answers

Percent means per____"

aalyn [17]

Means per hundred hope its right

7 0

3 years ago

Read 2 more answers

Which long division problem can be used to prove the formula for factoring the difference of two perfect cubes?

Mademuasel [1]

69
It’s 69

“Explaining “

4 0

3 years ago

Read 2 more answers

You have 4 one-dollar bills and 4 five-dollar bills in your piggy bank. You select two bills at random, with replacement. What i

Mkey [24]

The probability that one would have selected 2 five-dollar bills is; 1/4.

<h3>What is the probability you will have selected 2 five-dollar bills?</h3>

It follows from the task content that the piggy bank contains; 4 one-dollar bills and 4 five-dollar bills to make a total of 8 bills.

Hence, provided the probability events are carried out with replacement, the probability to have selected 2 five-dollar bills is;

= 4/8 × 4/8

= 1/4.

Read more on probability;

brainly.com/question/24756209

#SPJ1

5 0

2 years ago

Complete the steps to solve the polynomial equation x3 – 21x = –20. According to the rational root theorem, which number is a po

jeka94

Answer:

Zeroes : 1, 4 and -5.

Potential roots: $\pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20$ .

Step-by-step explanation:

The given equation is

$x^3-21x=-20$

It can be written as

$x^3+0x^2-21x+20=0$

Splitting the middle terms, we get

$x^3-x^2+x^2-x-20x+20=0$

$x^2(x-1)+x(x-1)-20(x-1)=0$

$(x-1)(x^2+x-20)=0$

Splitting the middle terms, we get

$(x-1)(x^2+5x-4x-20)=0$

$(x-1)(x(x+5)-4(x+5))=0$

$(x-1)(x+5)(x-4)=0$

Using zero product property, we get

$x-1=0\Rightarrow x=1$

$x-4=0\Rightarrow x=4$

$x+5=0\Rightarrow x=-5$

Therefore, the zeroes of the equation are 1, 4 and -5.

According to rational root theorem, the potential root of the polynomial are

$x=\dfrac{\text{Factor of constant}}{\text{Factor of leading coefficient}}$

Constant = 20

Factors of constant ±1, ±2, ±4, ±5, ±10, ±20.

Leading coefficient= 1

Factors of leading coefficient ±1.

Therefore, the potential root of the polynomial are $\pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20$ .

3 0

3 years ago