Could the solutions of a system of inequalities be a rectangular region? If so, give an example.
2 answers:
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Answer:
i hope this helps
Step-by-step explanation:
2 -16=0
+16 +16
2 =16
÷2 ÷2
= 8
=
x=
-5 +9=0
-9 -9
-5=-9
÷-5 ÷-5
=1.8
=
x=
6 -15=27
+15 +15
6 =42
÷6 ÷6
=7
=
x=
Answer:
Step-by-step explanation:
We will use 2 coordinates from the table along with the standard form for an exponential function to write the equation that models that data. The standard form for an exponential function is
where x and y are coordinates from the table, a is the initial value, and b is the growth/decay rate. I will use the first 2 coordinates from the table: (0, 3) and (1, 1.5)
Solving first for a:
. Sine anything in the world raised to a power of 0 is 1, we can determine that
a = 3. Using that value along with the x and y from the second coordinate I chose, I can then solve for b:
. Since b to the first is just b:
1.5 = 3b so
b = .5
Filling in our model:
Since the value for b is greater than 0 but less than 1 (in other words a fraction smaller than 1), this table represents a decay function.