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Nutka1998 [239]
3 years ago
15

Select the most SPECIFIC name for this shape

Mathematics
1 answer:
kykrilka [37]3 years ago
3 0

Answer:

Square

Step-by-step explanation:

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Find the measure of the indicated angle to the nearest degree
uranmaximum [27]
51 the other person was right
4 0
3 years ago
HELP PLEASE <br><br>i dont understand at all...
bija089 [108]

An exponent signifies repeated multiplication.

x\cdot x\cdot x=x^{3}  the factor x is repeated 3 times

Exponents can be added and subtracted to express the effects of multiplication and division.

\dfrac{x\cdot x\cdot x\cdot x\cdot x}{x\cdot x\cdot x}=\dfrac{x^{5}}{x^{3}}\\\\=\dfrac{x\cdot x\cdot x}{x\cdot x\cdot x}\cdot x\cdot x=x\cdot x\\\\=x^{(5-3)}=x^{2}

The addition and subtraction of exponents works the same even when there are more denominator factors than numerator factors.

\dfrac{x\cdot x\cdot x}{x\cdot x\cdot x\cdot x\cdot x}=\dfrac{x^{3}}{x^{5}}=\dfrac{1}{x^{2}}\\\\=x^{(3-5)}=x^{-2}

That is, a negative numerator exponent is the same as a positive denominator exponent and vice versa. You can move a factor with an exponent from denominator to numerator and change the sign of the exponent, and vice versa.

Your expression has 3 in the denominator with a negative exponent. It can be moved to the numerator and the exponent changed to positive:

\dfrac{1}{3^{-2}}=3^{2}\\\\=3\cdot 3=\bf{9}

8 0
3 years ago
Subtract 9 from 15 then multiply by 5
nlexa [21]
(15-9)*5= 30
The answer is 30
5 0
3 years ago
Read 2 more answers
Use the following steps to prove that log b(xy)- log bx+ log by.
borishaifa [10]

Answer with Step-by-step explanation:

a.x=b^p

y=b^q

Taking both sides log

log x=plog b

Using identity:logx^y=ylogx

p=\frac{logx}{log b}=log_b x

Using identity:log_x y=\frac{log y}{log x}

log y=qlog b

q=\frac{log y}{log b}=log_b y

b.xy=b^pb^q

We know that

x^a\cdot x^b=x^{a+b}

Using identity

xy=b^{p+q}

c.log_b(xy)=log_b(b^{p+q})

log_b(xy)=(p+q)log_b b

Substitute the values then we get

log_b(xy)=(log_b x+log_b y)

By using log_b b=1

Hence, log_b(xy)=log_b x+log_b y

3 0
3 years ago
Steven invests $20,000 in an account earning 3% interest, compounded annually for 10 years. Three years after Stevens's initial
Effectus [21]

The formula to find the amount is

here A is amount

P is the principal

'r' is the rate of interest

n is the number of years.

Case 1.

Stevan invests

P =$ 20,000

r = 3% = 0.03

n = 10 years

Hence the interest earned

= A - P = 26878.33 - 20000 = $6878.33

Case 2.

Evan invests

P = $10,000

r = 7% = 0.07

n = 7 years

Hence the interest earned

= A - P = 16057.81 - 10000 = 6057.81

Difference in the interest = 6878.33 - 6057.81 = $820.52

Rounded to the nearest dollar difference in interest = $821

6 0
3 years ago
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