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tatuchka [14]
3 years ago
8

An object travels around a circle of radius r with constant speed. If s is the distance traveled in time t around the circle and

theta is the central angle​ (in radians) swept out in time​ t, then the linear speed of the object is vequals​_____ and the angular speed of the object is omegaequals​______.
Mathematics
1 answer:
Alex3 years ago
4 0

Answer with Step-by-step explanation:

We are given that

Radius of circle=r

Total distance traveled =s

Time=t

Central angle=\theta rad

We know that

Linear speed,v=\frac{distance}{time}

Using the formula

Therefore, v=\frac{s}{t}

Angular speed,\omega=\frac{Angular\;displacement}{time}

By using the formula

\omega=\frac{\theta}{t} rad/s

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What is the product (3a2 b4) (- 8b3)
Anvisha [2.4K]

Answer:

-24 a^2 b^7

Step-by-step explanation:

Simplify the following:

-8×3 a^2 b^4 b^3

Hint: | Combine products of like terms.

3 a^2 b^4 (-8) b^3 = 3 a^2 b^(4 + 3) (-8):

-8×3 a^2 b^(4 + 3)

Hint: | Evaluate 4 + 3.

4 + 3 = 7:

-8×3 a^2 b^7

Hint: | Multiply 3 and -8 together.

3 (-8) = -24:

Answer: -24 a^2 b^7

6 0
3 years ago
Breanna purchased 8 oranges for $10.00. Jonathon purchased 6 oranges for $8.00. What was the unit rate for each purchase?
nataly862011 [7]

Answer:

Step-by-step explanation:

breanna's oranges were $1.25

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4 0
2 years ago
Solve the following system by the comparison method.
agasfer [191]

Answer:

2p + q = 1

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9p + 3(1 - 2p) + 3 = 0

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3p + 6 =0

3p = -6

p = -2

q = 1 - 2p

q = 1 -2(-2)

q = 1 + 4

q = 5

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there for the answer would be

{(-2, 5)}

Hopefully this was helpful <3 :3

5 0
3 years ago
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stellarik [79]

Vasellasar26,

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3 0
2 years ago
What is the first step in solving the equation 3.5 n + 6.4 = 42.5?
miss Akunina [59]

I would add like terms, meaning subtract 6.4 from both sides.

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7 0
3 years ago
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