Question

An object travels around a circle of radius r with constant speed. If s is the distance traveled in time t around the circle and theta is the central angle​ (in radians) swept out in time​ t, then the linear speed of the object is vequals​_____ and the angular speed of the object is omegaequals​______.

Answer 1

Answer with Step-by-step explanation:

We are given that

Radius of circle=r

Total distance traveled =s

Time=t

Central angle=$\theta$ rad

We know that

Linear speed,v=$\frac{distance}{time}$

Using the formula

Therefore, v=$\frac{s}{t}$

Angular speed,$\omega=\frac{Angular\;displacement}{time}$

By using the formula

$\omega=\frac{\theta}{t}$ rad/s