Ask question

Ask question

All categories

2 years ago

8

An object travels around a circle of radius r with constant speed. If s is the distance traveled in time t around the circle and

theta is the central angle (in radians) swept out in time t, then the linear speed of the object is vequals_____ and the angular speed of the object is omegaequals______.

1 answer:

Alex2 years ago

4 0

Answer with Step-by-step explanation:

We are given that

Radius of circle=r

Total distance traveled =s

Time=t

Central angle= $\theta$ rad

We know that

Linear speed,v= $\frac{distance}{time}$

Using the formula

Therefore, v= $\frac{s}{t}$

Angular speed, $\omega=\frac{Angular\;displacement}{time}$

By using the formula

$\omega=\frac{\theta}{t}$ rad/s

You might be interested in

What is the distance between the points (2,10) and (-6, 4) on the coordinate

stellarik [79]

Answer:

The distance between the given points (2,10) and (-6, 4) on the coordinate plane is 10units

Therefore distance s=10 units

Step-by-step explanation:

Given points are (2,10) and (-6, 4) on the coordinate plane

To distance between the given points :

The distance formula is $s=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ units

Let $(x_1,y_1)$ , $(x_2,y_2)$ be the given points (2,10) and (-6, 4) respectively

Now substituting the values in the distance formula we get

$s=\sqrt{(-6-2)^2+(4-10)^2}$

$=\sqrt{(-8)^2+(-6)^2}$

$=\sqrt{8^2+6^2}$

$=\sqrt{64+36}$

$=\sqrt{100}$

$=10$

Therefore s=10 units

The distance between the given points (2,10) and (-6, 4) on the coordinate plane is 10units

5 0

3 years ago

Use quadratic formula to find both solutions to the quadratic equation given below . 3x^2-5x-1=0

Rudiy27

Answer:

$x1=\frac{5+\sqrt{37}} {6}$

$x2=\frac{5-\sqrt{37}} {6}$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$3x^{2} -5x-1=0$

so

$a=3\\b=-5\\c=-1$

substitute in the formula

$x=\frac{5(+/-)\sqrt{(-5)^{2}-4(3)(-1)}} {2(3)}$

$x=\frac{5(+/-)\sqrt{37}} {6}$

$x1=\frac{5+\sqrt{37}} {6}$

$x2=\frac{5-\sqrt{37}} {6}$

8 0

2 years ago

Read 2 more answers

How to pass my regions

Anettt [7]

by studying because that's the hard truth

4 0

3 years ago

Read 2 more answers

If the outlier is excluded, what happens to the mode

slega [8]

Answer:

Outliers affect the mean value of the data but have little effect on the median or mode of a given set of data.

Is there any more details, I could give a better answer.

6 0

3 years ago

Suppose the cpi was 110 last year and is 121 this year. instructions: in part a, enter your answer as a whole number. in part b,

nexus9112 [7]

<span>To calculate the change in CPI we need to do a % change formula. (New - Old) / (Old) = n. (121 - 110) / 110 = .10. This is equal to a 10% change in CPI. To confirm the answer, do, (Old) * (1+n) = New CPI. 110*(1+.10) = 121. It equals so it is right!</span>

8 0

3 years ago