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BabaBlast [244]
3 years ago
10

The original price of a pair of shoes at DSW is $29.99. On Black Friday there is a mark down of 10%. What is the sale amount of

the pair of shoes?
Mathematics
1 answer:
Snowcat [4.5K]3 years ago
7 0

Answer:

The sale amount of the pair of shoes will be: $27

Step-by-step explanation:

The original price = $29.99

Mark down = 10%

Mark down amount = 10% × 29.99

                                 = 0.1 × 29.99

                                 = $2.99

Thus, the sale price = Original price - Mark down amount

                                 = $29.99 - $2.99

                                 = $27

Therefore,  the sale amount of the pair of shoes will be: $27

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Answer:

c = 6.1

Step-by-step explanation:

Given that: B = 18° , C = 152°,  and b = 4.

The missing side, c, can be determined by applying the sine rule which states that:

\frac{b}{Sin B} = \frac{c}{Sin C}

\frac{4}{Sin 18^{o} } = \frac{c}{Sin 152^{o} }

c = \frac{4* Sin 152^{o} }{Sin 18^{o} }

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denpristay [2]

Answer:

We conclude that the population mean light bulb life is at least 500 hours at the significance level of 0.01.

Step-by-step explanation:

We are given that a manufacturer produces light bulbs that have a mean life of at least 500 hours when the production process is working properly. The population standard deviation is 50 hours and the light bulb life is normally distributed.

You select a sample of 100 light bulbs and find mean bulb life is 490 hours.

Let \mu = <u><em>population mean light bulb life.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 500 hours      {means that the population mean light bulb life is at least 500 hours}

Alternate Hypothesis, H_A : \mu < 500 hours     {means that the population mean light bulb life is below 500 hours}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

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where, \bar X = sample mean bulb life = 490 hours

           σ = population standard deviation = 50 hours

           n = sample of light bulbs = 100

So, <u><em>the test statistics</em></u>  =  \frac{490-500}{\frac{50}{\sqrt{100} } }

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Since our test statistic is higher than the critical value of z as -2 > -2.33, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis.</u>

Therefore, we conclude that the population mean light bulb life is at least 500 hours.

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