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Lilit [14]
3 years ago
13

Which statements describe the graph of y = Negative RootIndex 3 StartRoot x minus 1 EndRoot + 2? Select three options.

Mathematics
2 answers:
Marysya12 [62]3 years ago
7 0

Answer:

The graph has a domain of all real numbers.

As x is increasing, y is decreasing

Step-by-step explanation:

The given function is y=-\sqrt[3]{x-1}+2

This is the graph of a cubic function that has been reflected in the y-axis, shifted 1 unit right, and shifted up 2 units.

The domain is all real numbers

The range is all real numbers

Y-decreases as x increases

When x=0 y=-\sqrt[3]{0-1}+2=3

When y=0 , 0=-\sqrt[3]{x-1}+2\implies x=4

Solnce55 [7]3 years ago
6 0

Answer:

options a and c

Step-by-step explanation:

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A coach chooses six out of eight players to go to a skills workshop. If order does not matter, in how many ways can he choose th
Serga [27]
A.6 BECAUSE THATS THE ANSWER
4 0
4 years ago
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Suppose u and v are functions of x that are differentiable at x=0 and that u(0)= 7,u'(0)=-5,v(0)= -1, v'(0)= -4.
andriy [413]

This question is incomplete, the complete question is;

Suppose u and v are functions of x that are differentiable at x=0

and that { u(0) = 7, u'(0) = -5 }  { v(0)= -1, v'(0) = -4 }

Find the values of the following derivatives at x = 0.

a) \frac{d}{dx}( uv )

b)  \frac{d}{dx}( \frac{u}{v} )

c)  \frac{d}{dx}( \frac{v}{u} )

Answer:

a) \frac{d}{dx}( uv ) = -23  

b) \frac{d}{dx}( \frac{u}{v} )  = 33

c) \frac{d}{dx}( \frac{v}{u} ) = -32/49 or - 0.6531

Step-by-step explanation:

Given that;

{ u(0) = 7, u'(0) = -5 }  { v(0)= -1, v'(0) = -4 }

a)

\frac{d}{dx}( uv )

we differentiate

\frac{d}{dx}( uv )  = uv' + vu'

at x = (0), we substitute our values

\frac{d}{dx}( uv ) = ( 7 × -4 ) + ( -1 × -5)

\frac{d}{dx}( uv )  = -28 + 5

\frac{d}{dx}( uv ) = -23  

b)

\frac{d}{dx}( \frac{u}{v} )

we differentiate

\frac{d}{dx}( \frac{u}{v} ) = ( vu' - uv' ) / v²

at x=0, we substitute our values

\frac{d}{dx}( \frac{u}{v} ) = ( (-1 × -5) - (7 × -4 ) ) / (-1)²

\frac{d}{dx}( \frac{u}{v} ) = (( 5 - ( -28 )) / 1

\frac{d}{dx}( \frac{u}{v} )  = 33 / 1

\frac{d}{dx}( \frac{u}{v} )  = 33

c) \frac{d}{dx}( \frac{v}{u} )

we differentiate

\frac{d}{dx}( \frac{v}{u} )  = ( uv' - vu' ) / u²

at x=0, we substitute our values

\frac{d}{dx}( \frac{v}{u} )  = ( (7 × -4) - (-1 × -4) ) / (7)²

\frac{d}{dx}( \frac{v}{u} ) = ( -28 - ( 4 ) ) / 49

\frac{d}{dx}( \frac{v}{u} )  = ( -28 - 4 ) /49

\frac{d}{dx}( \frac{v}{u} )  = -32 / 49

\frac{d}{dx}( \frac{v}{u} ) = -32/49 or - 0.6531

6 0
3 years ago
Find the volume of the solid below.
Wewaii [24]

Answer:

385 cm volume

Step-by-step explanation:

Length-- 7

width-- 5

height-- 1 1

Volume formula -- L times W times H = V.

Multiply all those and you get 385cm squared.

have a great Day!!!!!

4 0
3 years ago
The total charge on 4 particles is −36 units. All the particles have the same charge.
xxMikexx [17]

We are given

total number of particles =4

and

total sum of charge=-36

Since, all the particles have the same charge

and total charge is negative

so, charge on each particle must be negative

now, we can use formula to find change on each particle

charge on each particle = (total sum of charge)/( total number of particles)

now, we can plug values

and we get

The charge on each particle is

=\frac{-36}{4}

=-9 units..............Answer


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3 years ago
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15 AND 2. 
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