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3 years ago

Which statements describe the graph of y = Negative RootIndex 3 StartRoot x minus 1 EndRoot + 2? Select three options.

Mathematics

2 answers:

Marysya12 [62]3 years ago

7 0

Answer:

The graph has a domain of all real numbers.

As x is increasing, y is decreasing

Step-by-step explanation:

The given function is $y=-\sqrt[3]{x-1}+2$

This is the graph of a cubic function that has been reflected in the y-axis, shifted 1 unit right, and shifted up 2 units.

The domain is all real numbers

The range is all real numbers

Y-decreases as x increases

When x=0 $y=-\sqrt[3]{0-1}+2=3$

When y=0 , $0=-\sqrt[3]{x-1}+2\implies x=4$

Solnce55 [7]3 years ago

6 0

Answer:

options a and c

Step-by-step explanation:

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3 years ago

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Nesterboy [21]

Answer:

$\dfrac{1}{2}$

Step-by-step explanation:

Given the function $h(x)=\dfrac{1}{8}x^3-x^2$

The average rate of change of the function h(x) over the interval $a\le x\le b$ can be calculated using formula

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In your case,

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$\dfrac{h(2)-h(-2)}{2-(-2)}\\ \\=\dfrac{(\frac{1}{8}\cdot 2^3-2^2)-(\frac{1}{8}\cdot (-2)^3-(-2)^2)}{4}\\ \\=\dfrac{(1-4)-(-1-4)}{4}\\ \\=\dfrac{-3+5}{4}\\ \\=\dfrac{2}{4}\\ \\=\dfrac{1}{2}$

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3 years ago

(02.01 LC)

denis-greek [22]

Answer:

Step-by-step explanation:

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3 years ago

Find the value of i77.<br> A) 1 <br> B) i <br> C) −1 <br> D) −i

Colt1911 [192]

assuming you mean $i^{77}$ where $i=\sqrt{-1}$

ok, notice a pattern in the exponent

$i^1=i=\sqrt{-1}$

$i^2=-1$

$i^3=-\sqrt{-1}=-i$

$i^4=1$

$i^5=i=\sqrt{-1}$

hum, so it goes 1,2,3,4, then repeats

ok, so every 4, the cycle repeats

how far up is 77 from a multipule of 4?

4*19=76

76 is 1 away from 77

so $i^{77}=(i^{76})(i^1)=$

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the answer is B

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makkiz [27]

Answer:

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Step-by-step explanation:

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2 years ago