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4 years ago

Which situation can be modeled by the inequality 3x+5≥12]?

1 answer:

4 0

The answer is the last one with Amir as the 5 is the extra, and the 3 is multiplied by x or in this case days, and it is at least not equal.

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A certain shampoo is available in two sizes. A 12.6-ounce bottle costs $2.37. A 25.3-ounce bottle costs $5.24.

neonofarm [45]

Answer:

The 12.6 oz bottle

Step-by-step explanation:

0.19/oz for the 12.6 oz

0.21/oz for the 25.3 oz

4 0

3 years ago

O'Henry Elementary School has a chess club. Of the students in the sixth

kiruha [24]

Answer:

35% of the sixth grade is in the chess club

Step-by-step explanation:

if there are 100 students consider that as 100%

20 is a fifth of 100

20 x 5 =100

since 7/20 is a fraction you multiple the numerator (7) with the same number you multiplied to the denominator (20) which is 5.

7 x 5 = 35

35/100 = 35%

3 0

4 years ago

let BC be the vector with the given initial and terminal points, write BC as a linear combination if B(3, -1) and C(4,-7)

dmitriy555 [2]

The answer is b i hope you get it right

7 0

3 years ago

Tthe area of a circle increases at a rate of 5 cm^2/s.

abruzzese [7]

Answer:

(a) 0.198 cm/s (b) 1 cm/s

Step-by-step explanation:

It is given that,

The rate of change of area of a cicle, $\dfrac{dA}{dt}=5\ cm^2/s$

(a) The area of a circle is given by :

$A=\pi r^2$

Differentiate both sides,

$\dfrac{dA}{dt}=2\pi r\dfrac{dr}{dt}\\\\\text{Put the value of dA/dt and r = 4 cm}\\\\\dfrac{dr}{dt}=\dfrac{dA/dt}{2\pi r}\\\\\dfrac{dr}{dt}=\dfrac{5}{2\pi \times 4}\\\\\dfrac{dr}{dt}=0.198\ cm/s$

(b) Circumference, $C=2\pi r$ = 5 cm

$\dfrac{dA}{dt}=2\pi r\dfrac{dr}{dt}\\\\\dfrac{dr}{dt}=\dfrac{dA/dt}{2\pi r}\\\\\dfrac{dr}{dt}=\dfrac{5}{5}\\\\\dfrac{dr}{dt}=1\ cm/s$

Hence,

(a) 0.198 cm/s (b) 1 cm/s

6 0

3 years ago

If a student is taking classes, math, English, P.E., history, biology and Spanish, then what is the chance that the student will

madreJ [45]

Answer:

60%

Step-by-step explanation: i hope this heple

3 0

3 years ago