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likoan [24]
2 years ago
10

Can someone please help me with this

Mathematics
1 answer:
rjkz [21]2 years ago
6 0

Answer:

Each point reflected across the x-axis, goes from (x, y) --> (x, -y), which means that we keep the x coordinate the same, but multiply the y coordinate by -1:

L (-2, 4) --> (-2, -4)

M (2, 1) --> (2, -1)

N (-4, -3) --> (-4, 3)

Step-by-step explanation:

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1. Flight 202's arrival time is normally distributed with a mean arrival time of 4:30
Bezzdna [24]

Answer:

Step-by-step explanation:

1) Let the random time variable, X = 45min; mean, ∪ = 30min; standard deviation, α = 15min

By comparing P(0 ≤ Z ≤ 30)

P(Z ≤ X - ∪/α) = P(Z ≤ 45 - 30/15) = P( Z ≤ 1)

Using Table

P(0 ≤ Z ≤ 1) = 0.3413

P(Z > 1) = (0.5 - 0.3413) = 0.1537

∴ P(Z > 45) = 0.1537

2)  By compering (0 ≤ Z ≤ 15) ( that is 4:15pm)

P(Z ≤ 15 - 30/15) = P(Z ≤ -1)

Using Table

P(-1 ≤ Z ≤ 0) = 0.3413

P(Z < 1) = (0.5 - 0.3413) = 0.1587

∴ P(Z < 15) = 0.1587

3) By comparing P(0 ≤ Z ≤ 60) (that is for 5:00pm)

P(Z ≤ 60 - 30/15) = P(Z ≤ 2)

Using Table

P(0 ≤ Z ≤ 1) = 0.4772

P(Z > 1) = (0.5 - 0.4772) = 0.0228

∴ P(Z > 60) = 0.0228

6 0
3 years ago
Find the domain of the graphed function
andreev551 [17]

Answer:

D.

Step-by-step explanation:

Because the lowest point in the X coordinate is -4 and the highest point is 9.

6 0
2 years ago
How do I do problem twelve you don’t have to give the answer because you can’t see the numbers but explain how I would do It
liraira [26]

In order to do this you would multiply how much she used for 1/16 of the garden by 16. So 1/2 • 16 which is 8. So the answer is 8.

Hope this helps!

8 0
2 years ago
A strawberry weighs about 1 out of ten an orange. if an orange weighs about 67 grams, about how many grams does a strawberry wei
andre [41]

Answer:

16.75 g

Step-by-step explanation:

Orange's weight = 67 g

Strawberry's weight

= ¼ of the weight of orange

= ¼ × weight of orange

= ¼ × 67 g

= 67 g/4

= 16.75 g

8 0
2 years ago
Use the graph of f(x) below to estimate the value of f '(3):
klio [65]
Well, looking at the graph, notice, its vertex is at 0,9, and it passes through the points -3,0 and 3,0, so hmm let's use 3,0, to get the equation of f(x)

\bf ~~~~~~\textit{parabola vertex form}&#10;\\\\&#10;\begin{array}{llll}&#10;\boxed{y=a(x- h)^2+ k}\\\\&#10;x=a(y- k)^2+ h&#10;\end{array}&#10;\qquad\qquad&#10;vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\&#10;-------------------------------

\bf vertex~(0,9)~&#10;\begin{cases}&#10;h=0\\&#10;k=9&#10;\end{cases}\implies y=a(x-0)^2+9&#10;\\\\\\&#10;\textit{we also know that }&#10;\begin{cases}&#10;x=3\\&#10;y=0&#10;\end{cases}\implies 0=a(3-0)^2+9&#10;\\\\\\&#10;-9=9a\implies \cfrac{-9}{9}=a\implies -1=a\quad thus\quad \boxed{y=-x^2+9}&#10;\\\\\\&#10;\left. \cfrac{dy}{dx}=-2x \right|_{x=3}\implies -6
3 0
3 years ago
Read 2 more answers
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