Recall the sum identity for cosine:
cos(a + b) = cos(a) cos(b) - sin(a) sin(b)
so that
cos(a + b) = 12/13 cos(a) - 8/17 sin(b)
Since both a and b terminate in the first quadrant, we know that both cos(a) and sin(b) are positive. Then using the Pythagorean identity,
cos²(a) + sin²(a) = 1 ⇒ cos(a) = √(1 - sin²(a)) = 15/17
cos²(b) + sin²(b) = 1 ⇒ sin(b) = √(1 - cos²(b)) = 5/13
Then
cos(a + b) = 12/13 • 15/17 - 8/17 • 5/13 = 140/221
Answer: The answer is v=25.1 cm³
Step-by-step explanation:
b=4
h= 2
r= 4/2 r =2 radius is half of the diameter
V=πr²h
v= π(2)²2
v= 25.132741228718
v=25.1 cm³
Answer:
64.23%
Step-by-step explanation:
Percent error
(699-250)/699 x 100 = 64.23
