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3 years ago

7

What causes a solution to a rational equation to be an extraneous solution?

2 answers:

LenKa [72]3 years ago

6 0

its B just did the pre test

nika2105 [10]3 years ago

5 0

Answer: If a solution results in zero when subsitituted into the denominator of the equation, the solution is extraneous.

This is because you obtained the solution from a simplified version of the original equation, but you have to check if the solution obtained is a real solution of the original equation

In the case that when you substitute the solution in the original version the denominator becomes zero, this solution must be rejected, because the division by zero is not defined.

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Find the lateral surface area of the cylinder. Round your answer to the nearest tenth.

Svet_ta [14]

Answer:

A=2πrh

Step-by-step explanation:

A=2*22/7*4*9

=230

5 0

3 years ago

Find the rectangular coordinates of the point with the polar coordinates (3, 3 divided by 2 pi ). (1 point)

kifflom [539]

Answer:

The correct choice is (0,-3)

Step-by-step explanation:

To convert from polar coordinates to rectangular coordinates, we use the parametric equations:

$x=r\cos \theta$ and $y=r\sin \theta$

The point given to us in polar coordinates is $(3,\frac{3}{2}\pi)$ .

where $r=3,\theta=\frac{3\pi}{2}$

$x=3\cos (\frac{3\pi}{2})$ and $y=3\sin( \frac{3\pi}{2})$

$x=3(0)$ and $y=3(-1)$

$x=0$ and $y=-3$

The correct choice is (0,-3)

5 0

3 years ago

−2n < −12 <br> how can i slove this?

Ket [755]

Answer:

n>6

Step-by-step explanation:

you need to find the n variable by dividing

8 0

3 years ago

Read 2 more answers

Two similar circles are shown. The circumference of the larger circle, with radius OB, is 3 times the circumference of the small

zheka24 [161]

Answer:

The circumference of the smaller circle is:

C = 2*pi*x/3

Step-by-step explanation:

We know that for a circle of radius R the circumference is given by:

C = 2*pi*R

where pi = 3.14...

Here we have two circles, A and B, where B is the larger circle and A is the smaller circle.

We know that:

The circumference of B is 3 times the circumference of A.

The radius of circle B is: OB = x

The radius of circle A is: OA

We want to find an expression of OA.

The circumference of circle B will be:

C(B) = 2*pi*OB = 2*pi*x

The circumference of circle A will be:

C(A) = 2*pi*OA

And we know that the circumference of circle B is 3 times the circumference of circle A, then:

C(B) = 3*C(A)

replacing the equations for the circumferences, we get:

2*pi*x = 3*(2*pi*OA)

dividing both sides by 2*pi, we get:

x = 3*OA

Now we want to solve this for OA, then we need to isolate it,

x/3 = OA

We can conclude that the radius of the smaller circle is equal to x/3.

Then the circumference of circle A is:

C(A) = 2*pi*x/3

5 0

2 years ago

Surface area for a rectangular prism 43in 19in 35in

Ugo [173]

A = 2lw + 2lh + 2wh
A = 2(43)(19) + 2(43)(35) + 2(19)(35)
A = 2(817) + 2(1505) + 2(665)
A = 1634 + 3010 + 1330
A = 5974in²

5 0

3 years ago