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sladkih [1.3K]
3 years ago
15

Need help with these two math problems

Mathematics
1 answer:
Gnom [1K]3 years ago
8 0

Answer:

y = (x - 1)(x - 3)

y = (x + 2)^2

Step-by-step explanation:

3)

Has roots at x = {1, 3}

y = (x - 1)(x - 3)

4)

Has double root at x = -2

y = (x + 2)^2

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Please help me thank you I appreciate it
olganol [36]

Answer:

73

Step-by-step explanation:

since it's a right angle it equals 90° and you already know there 17°. so you just subtract 90-17

8 0
3 years ago
I need to find Ac the equation are ae=+50 and ce=+32
lara [203]
The answer to the problem is +18.
6 0
3 years ago
Gary mails 10^3 flyers to clients in one week. How many flyers does Gary mail?
Bogdan [553]
How much flyers does Gary mail in what? a week or a day?

If you are referring to week: Simply simplify 10³.

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3 0
3 years ago
1/sin10°-√3/cos10°=4​
Alexandra [31]

Answer:

\frac{1}{\sin \left(10^{\circ \:\:}\right)}\:\:\frac{1}{\sin \:\left(10^{\circ \:\:}\right)}=4

Step-by-step explanation:

Given the expression

\frac{1}{\sin \left(10^{\circ \:}\right)}-\frac{\sqrt{3}}{\cos \left(10^{\circ \:}\right)}=4

Taking the left-hand side and solving it

\frac{1}{\sin \left(10^{\circ \:}\right)}-\frac{\sqrt{3}}{\cos \left(10^{\circ \:}\right)}

as

\frac{1}{\sin \:\left(10^{\circ \:\:}\right)}=5.76

and

\frac{\sqrt{3}}{\cos \left(10^{\circ \:\:}\right)}=1.76

so the expression becomes

\frac{1}{\sin \left(10^{\circ \:\:}\right)}\:\:\frac{1}{\sin \:\left(10^{\circ \:\:}\right)}=5.76-1.76

                           =4

Thus, we conclude that

\frac{1}{\sin \left(10^{\circ \:\:}\right)}\:\:\frac{1}{\sin \:\left(10^{\circ \:\:}\right)}=4

8 0
3 years ago
-6x-8<4 plz help me this is sixty percent of my grade
masya89 [10]

Answer:

x>-2

Step-by-step explanation:

5 0
3 years ago
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